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miskamm [114]
4 years ago
6

Which of the following outer electron configurations would you expect to belong to a reactive metal?

Chemistry
1 answer:
AURORKA [14]4 years ago
7 0

Answer:

The answer to your question is: a

Explanation:

Electron configurations are:

ns is for alkali metals and alkali earth metal

nd is for transition metals

nf is for Inner transition metals

np is for nonmetals

np⁶ is for noble gases

a. ns2  This is the electron configuration of an alkali earth metal

b. ns2 np6  This is the electron configuration of a noble gas

c. ns2 np5  This is the electron configuration of nonmetals

d. ns2 np2 This is the electron configuration of nonmetals

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A balloon has a volume of 125mL with 10 pumps of gas. The balloon is reduced in volume to 88mL, how much gas is in the balloon?
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Answer:

7.04

Explanation:

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3 years ago
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6 0
3 years ago
a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
zhannawk [14.2K]
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr

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Hope this helps!
3 0
4 years ago
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4 0
3 years ago
calculate the number of moles of sulfuric acid that is contained in 250 mL of 8.500 M sulfuric acid solution
san4es73 [151]

Answer : The moles of H_2SO_4 are, 2.125 mole.

Explanation : Given,

Molarity of H_2SO_4 = 8.500 M

Volume of solution = 250 mL  = 0.250 L    (1 L = 1000 mL)

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

8.500M=\frac{\text{Moles of }H_2SO_4}{0.250L}

\text{Moles of }H_2SO_4=2.125mol

Therefore, the moles of H_2SO_4 are, 2.125 mole.

5 0
3 years ago
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