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3 years ago

Can somebody plz answer a.b.c (just make it 1 sentence for each)

Chemistry

2 answers:

Maurinko [17]3 years ago

8 0

Answer:

One sentence that can be written for evidence is:

Fossils. Fossils document the existence of now-extinct past species that are related to present-day species.

Eddi Din [679]3 years ago

7 0

Answer:

I think this is your answer. if I am right so.

Please mark me as brainliest. thanks!!

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LenKa [72]

Answer:

hahahh noob

Explanation:

3 0

3 years ago

Thermal energy chemical change lab report

natulia [17]

Answer:

This is required answer.

Explanation:

Given that,

Thermal energy chemical change lab report

We know that,

Thermal energy :

When we rise a temperature of any substance then the molecules of substance moves fastly then the heat produced. It is called thermal energy.

Chemical change in the thermal energy :

When we heat a substance then the thermal energy increases and the molecules of substance moves fastly. That means the chemical bonds are break in reactants due to energy.

In products, The new chemical bonds are create due to energy.

For example ; The coal is burned then produced heats water and change it into steam.

Hence, This is required answer.

5 0

3 years ago

2. Consider the reaction 2NO(g) + O2(g) → 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is r

vredina [299]

Answer :

(a) The rate of $NO_2$ formed is, 0.066 M/s

(b) The rate of $O_2$ formed is, 0.033 M/s

Explanation : Given,

$\frac{d[NO]}{dt}$ = 0.066 M/s

The balanced chemical reaction is,

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate of disappearance of $NO$ = $-\frac{1}{2}\frac{d[NO]}{dt}$

The rate of disappearance of $O_2$ = $-\frac{d[O_2]}{dt}$

The rate of formation of $NO_2$ = $\frac{1}{2}\frac{d[NO_2]}{dt}$

As we know that,

$\frac{d[NO]}{dt}$ = 0.066 M/s

(a) Now we have to determine the rate of $NO_2$ formed.

$\frac{1}{2}\frac{d[NO_2]}{dt}=\frac{1}{2}\frac{d[NO]}{dt}$

$\frac{d[NO_2]}{dt}=\frac{d[NO]}{dt}=0.066M/s$

The rate of $NO_2$ formed is, 0.066 M/s

(b) Now we have to determine the rate of molecular oxygen reacting.

$-\frac{d[O_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}$

$\frac{d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

The rate of $O_2$ formed is, 0.033 M/s

6 0

3 years ago

If the pH of the solution is 10, what is the [OH-] concentration?

swat32

Answer:

1× $10^{-4}M$

Explanation:

To solve this, you will need to do multiple steps.

Firstly, you will have to convert to pOH from pH, which is done by simply subtracting 14-10 to get a pOH of 4.

Then, use the following formula to calculate the [OH-} concentration:

[OH-]= $10^{-pOH}$

When converted to Scientific Notation, you get a resulting answer of

1× $10^{-4}M$ .

5 0

3 years ago

Which object has particles with the most kinetic energy?

Pavlova-9 [17]

Answer:

Explanation:

because it is moving so it has kinetic energy

6 0

3 years ago