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svetoff [14.1K]
3 years ago
5

A speeding car is going 72 mi/hr. The driver hits the brakes to slow the car down to the 45 mi/hr speed limit. The car has a mas

s of 1.0 metric tons. What is the magnitude of the impulse on the car?
Physics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

I = -12070 N.s

Explanation:

Given that:

mass of 1.0 metric tons = 1000 kg

initial speed = 72mi/hr = 32.19 m/s

final speed = 45mi/hr = 20.12 m/s

Impulse = change in momentum

I = mv-mu

I = m(v-u)

I = 10³(20.12 - 32.19)

I = 10³(-12.07)

I = -12070 N.s

The negative  sign signifies that the impulse way is to the opposite direction.

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<h2>Answer:</h2>

0.46Ω

<h2>Explanation:</h2>

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R₂ = \frac{V^{2} }{P}    --------------------------------(iv)

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V = 12.0V

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R₂ = \frac{12.0^{2} }{4}

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\frac{1}{R_{X} } = \frac{1}{R_1} + \frac{1}{R_2}       -----------------(v)

Substitute the values of R₁ and R₂ into equation (v) as follows;

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12.0 = 11.7 + 0.65r

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r = 0.46Ω

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