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Thepotemich [5.8K]
3 years ago
12

ANYONE help me with this

Physics
1 answer:
ycow [4]3 years ago
8 0

Displacement is simply the change in position, or the difference in the final and initial positions:

\Delta d = d_f - d_i

Then

(a) ∆<em>d</em> = 5 m - 0 m = 5 m

(b) ∆<em>d</em> = 1 m - (-2 m) = 1 m + 2 m = 3 m

(c) ∆<em>d</em> = 2 m - (-2 m) = 2 m + 2 m = 4 m

(d) ∆<em>d</em> = 6 m - 2 m = 4 m

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A train travels 190km in 3.0 hours and then 120 km in 2.0 hours. What is it’s average speed ?
xxMikexx [17]

Answer:

60 km/h

Explanation:

Simplify the speed:

120÷2=60

Hence, the average speed is 60 km/h.

6 0
2 years ago
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andreev551 [17]

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3 0
3 years ago
Read 2 more answers
Mr. Miles zips down a water-slide starting at 15 m vertical distance up the scaffolding. Disregarding friction, what is the velo
lilavasa [31]

Answer:

The velocity of the Mr. miles is 17.14 m/s.

Explanation:

It is given that,

Mr. Miles zips down a water-slide starting at 15 m vertical distance up the scaffolding, h = 15 m

We need to find the velocity of the Mr. Miles at the bottom of the slide. It is a case of conservation of energy which states that the total energy of the system remains conserved. Let v is the velocity of the Mr. miles. So,

v=\sqrt{2gh}

g is the acceleration due to gravity

v=\sqrt{2\times 9.8\times 15}

v = 17.14 m/s

So, the velocity of the Mr. miles is 17.14 m/s. Hence, this is the required solution.

5 0
3 years ago
50g of ice at 0°C is mixed with 50g of water at 80°C, what will be the final temperature of a mixture in
xxTIMURxx [149]

Answer:

0° C

Explanation:

Given that

Mass of ice, m = 50g

Mass of water, m(w) = 50g

Temperature of ice, T(i) = 0° C

Temperature of water, T(w) = 80° C

Also, it is known that

Specific heat of water, c = 1 cal/g/°C

Latent heat of ice, L(w) = 89 cal/g

Let us assume T to be the final temperature of mixture.

This makes the energy balance equation:

Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C

m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have

50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)

4000 + 50T = 4000 - 50T

0 = 100 T

T = 0° C

Thus, the final temperature is 0° C

3 0
3 years ago
I need help with this physics question
insens350 [35]
It's impossible to describe WHERE a place is without mentioning ANOTHER place.

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The question is trying to get you to realize that to get from a reference point to a certain position, you have to know

How far
and
In what direction.
4 0
3 years ago
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