An object is moving with constant velocity downwards on a frictionless inclined plane that makes an angle of θ with the horizontal.
1. Which direction does the force of gravity act on the object?
2. Which direction does the normal force act on the object?
Which force is responsible for the object moving down the incline?
Answer:
The answer is below
Explanation:
1. When an object is moving with a constant velocity, the direction the force of gravity act on the object is DIRECTLY DOWN.
2. When an object is moving with a constant velocity, the direction the normal force act on the object "perpendicular to the surface of the plane."
3. When an object is moving with a constant velocity, the force that is responsible for the object moving down the incline is "the component of the gravitational force parallel to the surface of the inclined plane."
Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length
![\Delta L=L_{2}-L_{1}](https://tex.z-dn.net/?f=%5CDelta%20L%3DL_%7B2%7D-L_%7B1%7D)
![\Delta L=74.7-58.6](https://tex.z-dn.net/?f=%5CDelta%20L%3D74.7-58.6)
![\Delta L=16.1\ m](https://tex.z-dn.net/?f=%5CDelta%20L%3D16.1%5C%20m)
For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength
![\lambda=2\Delta L](https://tex.z-dn.net/?f=%5Clambda%3D2%5CDelta%20L)
Put the value into the formula
![\lambda=2\times16.1](https://tex.z-dn.net/?f=%5Clambda%3D2%5Ctimes16.1)
![\lambda=32.2\ cm](https://tex.z-dn.net/?f=%5Clambda%3D32.2%5C%20cm)
We need to calculate the frequency of the tuning
Using formula of frequency
![f=\dfrac{v}{\lambda}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7Bv%7D%7B%5Clambda%7D)
Put the value into the formula
![f=\dfrac{343}{32.2\times10^{-2}}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B343%7D%7B32.2%5Ctimes10%5E%7B-2%7D%7D)
![f=1065.2\ Hz](https://tex.z-dn.net/?f=f%3D1065.2%5C%20Hz)
![f=1.065\ kHz](https://tex.z-dn.net/?f=f%3D1.065%5C%20kHz)
Hence, The frequency of the tuning is 1.065 kHz
Answer:
60kgm/s
Explanation:
Given parameters:
Mass of frisbee = 5kg
Final speed = 12m/s
Unknown:
Impulse of the frisbee = ?
Solution:
The impulse of the frisbee is the same as the change in momentum.
It is given as:
Impulse = mass (Final velocity - Initial velocity)
Impulse = 5(12 - 0) = 60kgm/s