If HST has a tangential speed of 7,750 m/s, how long is HST’s orbital period? The radius of Earth is 6.38 × 106 m. s

the amplitude of the wave is which of the following A. Resonance B. Reflection C. Energy D. Magnitude

OLga [1]

D.Magnitude is the answer

8 0

3 years ago

What is an odometer?

ra1l [238]

Answer:

It is a instrument used to measure the distance traveled by a vehicle.

Explanation:

This is what it looks like ↓

6 0

3 years ago

Read 2 more answers

What are the three ways that a person can manipulate light?

BARSIC [14]

The three ways a person can manipulate light would be the following:, filter, and the time the photograph is taken

1. Angle - The camera angle marks the specific location at which the movie camera or video camera is placed to take a shot.

2. Filter - Camera lens filters still have many uses in digital photography, and should be an important part of any photographer's camera bag.

3. Time the photograph is taken - The golden hour, sometimes called the "magic hour", is roughly the first hour of light after sunrise, and the last hour of light before sunset, although the exact duration varies between seasons. During these times the sun is low in the sky, producing a soft, diffused light which is much more flattering than the harsh midday sun that so many of us are used to shooting in.

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

6 0

3 years ago

How do climate differences affect the movement at the Mariana Trench

vovangra [49]

It pushes the currents to opposite sides

8 0

3 years ago

slader the cross section of a 5-ft long trough is an isosceles trapezoid with a 2 foot lower base, a 3-foot upper base, and an a

Ostrovityanka [42]

Answer:

0.08 ft/min

Explanation:

To get the speed at witch the water raising at a given point we need to know the area it needs to fill at that point in the trough (the longitudinal section), which is given by the height at that point.

So we need to get the lenght of the sides for a height of 1 foot. Given the geometry of the trough, one side is the depth d and the other (lets call it l) is given by:

$l=\frac{3-2}{2}\,ft+2\,ft\\l=2.5\,ft$

since the difference between the upper and lower base is the increase in the base and we are only at halft the height.

Now we can calculate the longitudinal section A at that point:

$A=d\times l\\A=5\,ft \times 2.5\, ft\\A=12.5\, ft^{2}$

And the raising speed v of the water is given by:

$v=\frac{q}{A}\\v=\frac{1\, \frac{ft^3}{min}}{12.5\, ft^2}\\v=0.08\, \frac{ft}{min}$

where q is the water flow (1 cubic foot per minute).

7 0

3 years ago