Same as all the other ones like this.
Since the two figures are similar . . .
-- The ratio of of their volumes is R³ .
-- The ratio of their surface areas is R² .
-- The ratio of their dimensions is R .
So R³ is 729 / 2744 .
Take the cube root of that and you'll have R .
Then square R and you'll have the ratio of their surface areas.
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
Your molarity would be 0.975 M HCl because it’s moles of solute divided by liters of solvent
I believe that the answer for y is...
y= -ax+c/b