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3 years ago

Someone help me solve this please, I'd appreciate it if you can walk me through the steps. If not, just answering it is okay :)

Mathematics

1 answer:

DiKsa [7]3 years ago

7 0

Answer:

Step-by-step explanation:

I'm pretty sure

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Is 33,44,55 a right triangle?

Paul [167]

Answer:

Yes!

Step-by-step explanation:

We know that right triangles follow the Pythagorean Theorem, where

$a^{2} + b^{2} = c^{2}$

So we will put our side lengths into this formula, keeping in mind that c = the hypotenuse, which is the longest side. a and b are fairly arbitrary.

$33^{2} + 44^{2} = 55^{2}$

If this works, we know it's a right triangle.

1089 + 1936 = 3025

3025 = 3025

It worked! It's a right triangle!!

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2 years ago

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Please help what is the square root of 4774858 please help

Ad libitum [116K]

The square root of this is:

√ 4774858= 2185.145 or 2185.14

4 0

2 years ago

Zach is 3 years older than twice his sister Maya’s age.

Flauer [41]

The answer is z=2m+3 so the first one is right

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3 years ago

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What's the answer to this question round 6,584,003 to the nearest 100,1000,10,000

yawa3891 [41]

100,1000,10,000 is the correct answer or maybe 0

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3 years ago

Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

lisov135 [29]

Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

$\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}$

Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

$x=\frac{5+3y}{2}$

Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

3 0

3 years ago