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erastova [34]
3 years ago
7

What is 987 in expanded notation as an addition expression

Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0
900+80+7=987... hope it helps?
Elena L [17]3 years ago
3 0
Well 900 + 80 + 7 = 987
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Someone please help me with this!!!
Alexxx [7]
34.I
for this problem you just multiply the 20 by 2=40
and then you add 40+3=43
which will equal
\frac{43}{20}


35.G
if you divide
58 \div 25 = 2.32
so G
\frac{58}{25}

36. C
\frac{5}{5}  = 1
so if you subtract
\frac{6}{5}  -  \frac{5}{5}
will equal

\frac{1}{5}
1 \frac{1}{5}
7 0
3 years ago
Read 2 more answers
6
romanna [79]

Answer:

(-1,5)

(0,2)

(-1,1)

(2,-4)

8 0
3 years ago
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Use FOIL to explain how to find the product of (a + b)(a − b). Then describe a shortcut that you could use to get this product w
xenn [34]

Answer:

The product of (a+b)(a-b)  is a^2 - b^2

Step-by-step explanation:

Use FOIL to explain how to find the product of (a + b)(a − b)

FOIL is

Multiply First terms : a*a = a^2

Multiply Outside terms : a* -b = -ab

Multiply Inner  terms : b * a= ab

Multiply last terms : b * -b = -b^2

now we combine all the terms

a^2 -ab+ab - b^2

combine like terms

a^2 - b^2

The product of (a+b)(a-b)  is a^2 - b^2

Shortcut is we apply an identity

a^2 - b^2 = (a+b)(a-b)

8 0
3 years ago
Read 2 more answers
What is 29/33 in simplest form
Oduvanchick [21]
29/33 is already in simplest fraction form

29 is a prime number and cannot be simplified more
6 0
3 years ago
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What net force will make a 5 kg bowling ball accelerate by 1.5 m/s square 2?
s2008m [1.1K]

In pure translation or in roll without slip?

In pure translation, just use Fnet = m*a.  Fnet = 7.5 Newtons

In roll without slip it has effectively more inertia than 5 kilograms.  The effective inertia can be found as:

m_effective = m + I/r^2

For a uniform solid sphere, I = 2/5*m*r^2

So m_effective = 7/5*m

To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).

i hope this is what ur looking for

3 0
3 years ago
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