Given:

To find:
Select the true statements from the given options about the given value.
Solution:
We have,

It can be written as

![[\because \log(ab)=\log a+\log b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%28ab%29%3D%5Clog%20a%2B%5Clog%20b%5D)



Clearly, the value of x lies between 4 and 5. So,
and
.
Therefore, the correct options are C and D.
Answer:
that is the solution to the question
Answer:
a) 0.75 inch/month
b) y-20 = 0.75(x-4)
c) 17 inches
d) 44
a) 0.8 inch/month
b) yes
c) y = 0.8x + 18.8
d) 18.8 inches
Step-by-step explanation:
a) (21.5-20)/(6-4) = 1.5/2
= 0.75 inch/month
If this is correct, 2 months after the 6th month (month 8), it should be
21.5 + 2(0.75) = 23
Which it is
b) y-y1 = m(x-x1)
Where y is the length, x is the months, m is the slope and (x1,y1) is a known point
At x = 4, y = 20
y-20 = 0.75(x-4)
Or
y = 0.75x + c
20 = 0.75(4) + c
c = 20 - 3 = 17
y = 0.75x + 17
c) at birth, 4 months before month 4
So, 20 - 0.75(4) = 17
Which is also the y-intercept
d) y = 0.75(36) + 17
y = 27 + 4 = 44 inches
Generally, at the age of 3 years (36 month) the length is between 35 and 40 inches
a) slope = (30-22)/(14-4)
= 0.8 inch/month
b) 0.8 > 0.75, so yes
c) When x = 4, y = 22
y-22 = 0.8(x - 4)
y - 22 = 0.8x - 3.2
y = 0.8x + 18.8
y-intercept is 18.8
d) at birth, x = 0.
Length was 18.8 inches
Step-by-step explanation:
Answer:
Step-by-step explanation:
When we want to find the distance between two integers using the difference, the best way is to plot them on number line. And then count distance between them.
For example -3 and -1.
When we want to find difference we have:
-3-(-1)=-2
But distance can not be negative.
Now, we need to count distance between numbers -3 and -1 on the number line.
So we have from -3 to -2, one place and from -2 to -1 one place it is 2 places.
So distance is 2.
Answer: 12
Step-by-step explanation:
18−2(10+8)/6
=18−(2)(18)/6
=18−36/6
=18−6
=12