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katrin [286]
3 years ago
11

What is the equation of the line in the following graph? 1)y=x+2

Mathematics
1 answer:
Levart [38]3 years ago
8 0

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (2, 0) and (-2, -4). Substitute:

m=\dfrac{-4-0}{-2-2}=\dfrac{-4}{-4}=1

Therefore we have the equation of a line

y=1x+b\to y=x+b

Put the coordinates of the point (2, 0) to the equation:

0=2+b     <em>subtract 2 from both sides</em>

-2=b\to b=-2

Answer: \boxed{y=x-2}\to\boxed{3)}

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Step-by-step explanation:

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What is the equation for the plane illustrated below?
TiliK225 [7]

Answer:

Hence, none of the options presented are valid. The plane is represented by 3 \cdot x + 3\cdot y + 2\cdot z = 6.

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

a\cdot x + b\cdot y + c\cdot z = d

Where:

x, y, z - Orthogonal inputs.

a, b, c, d - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0),  (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

y = m\cdot x + b

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where:

m - Slope, dimensionless.

x_{1}, x_{2} - Initial and final values for the independent variable, dimensionless.

y_{1}, y_{2} - Initial and final values for the dependent variable, dimensionless.

b - x-Intercept, dimensionless.

If x_{1} = 2, y_{1} = 0, x_{2} = 0 and y_{2} = 2, then:

Slope

m = \frac{2-0}{0-2}

m = -1

x-Intercept

b = y_{1} - m\cdot x_{1}

b = 0 -(-1)\cdot (2)

b = 2

The equation of the line in the xy-plane is y = -x+2 or x + y = 2, which is equivalent to 3\cdot x + 3\cdot y = 6.

yz-plane (0, 2, 0) and (0, 0, 3)

z = m\cdot y + b

m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}

Where:

m - Slope, dimensionless.

y_{1}, y_{2} - Initial and final values for the independent variable, dimensionless.

z_{1}, z_{2} - Initial and final values for the dependent variable, dimensionless.

b - y-Intercept, dimensionless.

If y_{1} = 2, z_{1} = 0, y_{2} = 0 and z_{2} = 3, then:

Slope

m = \frac{3-0}{0-2}

m = -\frac{3}{2}

y-Intercept

b = z_{1} - m\cdot y_{1}

b = 0 -\left(-\frac{3}{2} \right)\cdot (2)

b = 3

The equation of the line in the yz-plane is z = -\frac{3}{2}\cdot y+3 or 3\cdot y + 2\cdot z = 6.

xz-plane (2, 0, 0) and (0, 0, 3)

z = m\cdot x + b

m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}

Where:

m - Slope, dimensionless.

x_{1}, x_{2} - Initial and final values for the independent variable, dimensionless.

z_{1}, z_{2} - Initial and final values for the dependent variable, dimensionless.

b - z-Intercept, dimensionless.

If x_{1} = 2, z_{1} = 0, x_{2} = 0 and z_{2} = 3, then:

Slope

m = \frac{3-0}{0-2}

m = -\frac{3}{2}

x-Intercept

b = z_{1} - m\cdot x_{1}

b = 0 -\left(-\frac{3}{2} \right)\cdot (2)

b = 3

The equation of the line in the xz-plane is z = -\frac{3}{2}\cdot x+3 or 3\cdot x + 2\cdot z = 6

After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

a = 3, b = 3, c = 2, d = 6

Hence, none of the options presented are valid. The plane is represented by 3 \cdot x + 3\cdot y + 2\cdot z = 6.

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3 years ago
What is the equation of the line with a slope of 4/3 and y-intercept of -6
skelet666 [1.2K]

Answer:

y=4/3x-6

Step-by-step explanation:

y=mx+b

m= 4/3

b= -6


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Answer:

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Step-by-step explanation:

blue is natural: 1, 4, 0, 2 and root of 25.

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white is real numbers.

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2 years ago
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