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sladkih [1.3K]
3 years ago
6

Please help 30 points

Mathematics
1 answer:
butalik [34]3 years ago
7 0
The answer would be About 2.08
You might be interested in
Given triangle DEF where ∠D = (7b +1)∘, ∠E = (2b + 1)∘, and ∠F = ( b + 8)∘. What is the measure of ∠E?
____ [38]
<h3>Answer:  35 (choice C)</h3>

=============================================

Explanation:

For any triangle, the three interior angles always add to 180.

D+E+F = 180

(7b+1) + (2b+1) + (b+8) = 180

(7b+2b+b) + (1+1+8) = 180

10b+10 = 180

10b = 180-10

10b = 170

b = 170/10

b = 17

Use this value of b to find the three angle measures

  • D = 7b+1 = 7*17+1 = 119+1 = 120
  • E = 2b+1 = 2*17+1 = 34+1 = 35 degrees
  • F = b+8 = 17+8 = 25

As a check,

D+E+F = 120+35+25 = 120+60 = 180

which helps confirm the correct answers.

3 0
3 years ago
I need help please help me ;-;
vodomira [7]

Answer:

I think option A is correct answer

3 0
3 years ago
Read 2 more answers
Find the values of x and y
Anastasy [175]

Answer:

X=20

Y=70

Step-by-step explanation:

All angles within a triangle add up to 180

180 - 40 = 140

140 is the top angle of the big triangle

140 + x + x = 180

x = 20

Now use x to find y by subtracting from the right angle (90 degrees)

90 - 20 = 70

70 + 40 + y = 180

Y = 70

8 0
3 years ago
A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
3 years ago
A group of students measured the lengths of their shoes. The lengths are listed in the table. Use the table to locate the incorr
Maru [420]

I think the incorrect data is the second x to the left.

3 0
2 years ago
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