Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the question the equation is
y = 4x − 11
Comparing with the general equation above
<h3>Slope = 4</h3><h3>y - intercept = - 11 or ( 0 , - 11)</h3>
Hope this helps you
Set up the given triangle on x-y coordinates with right angle at (0,0). So the two vertices are at (5,0) and (0,2
![sqrt{x} n]{3}](https://tex.z-dn.net/?f=sqrt%7Bx%7D%20n%5D%7B3%7D%20)
)
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>

for a pt (x,y) on line sx+ty=1, the minimum of

equals to

smallest value happens at

so area is

hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
Order the following numbers from greatest to least: 2, -1 , 2.58, -1.65. -1, -1.65, 2, 2.58 2.58, 2, -1.65, -1 2.58, 2, -1 , -1.
saw5 [17]
2.58, 2.58, 2.58, 2.58, 2.58, 2, 2, 2, 2, 2, -1, -1, -1, -1, -1, -1.65, -1.65, -1.65, -1.65, -1.65.

=========================================================

=========================================================