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3 years ago

Determine the area of the shaded region express your answer in simplest form?

1 answer:

5 0

Without so much as a quick peek at the picture, it's not possible to even begin
to answer the question. That's the reason, you see, that the picture is printed
right there, along with the question, in the same place from which you copied
this cut-off portion of the question. It's not enough. We need the picture too.

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What is perpendicular to y=-1/2x+11

ratelena [41]

You have to find the reciprocal of the gradient - 1/2
And to do that just flip the sign and fraction:
-1/2
1/2
2/1

So the answer is,
Y = 2x + 11

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3 years ago

7*z^(1/2)-3=2*z??? solve??/

Hoochie [10]

Answer:

Z €{9, i can right a fraction but on top is 9 below is 4}

Step-by-step explanation:

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3 years ago

URGENT DUE IN 20 MINUTES FOR GRADE PLEASE HELP<br> 2/3 (x-7)= -2

ASHA 777 [7]

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3 years ago

Can someone help me out with this at all?

dsp73

Answer:

1 maps to 1

2 maps to 3

3 maps to 2

Step-by-step explanation:

the correctly assigned answer options describe everything.

there is not much else to say and explain.

these are all true statements due to the symmetry principle of a circle.

when 2 direct connections of two points on the circumference of a circle have the same length, then also their bent distances on the circumference of the circle are the same. and vice versa.

and yes, the perpendicular radius (or diameter) of the circle towards such a line cuts this line in half.

6 0

3 years ago

The angles of depression of two ships from the top of the light house are 45° and 30° towards east. If the ships are 200 m apart

azamat

Answer:

273 meters

Step-by-step explanation:

See image attached for the diagram I used to represent this scenario.

The distance between the ships, at angles 30 and 45, is 200 meters. The distance between the left ship and the lighthouse is x meters.

We can use trigonometric ratios to solve this problem. We can use the tangent ratio $\big{(} \frac{\text{opposite}}{\text{adjacent}} \big{)}$ to create an equation with the two angles.

$\displaystyle \text{tan(45)} = \frac{h}{x}$
$\displaystyle \text{tan(30)} = \frac{h}{x+200} }$

Let's take these two equations and solve for x in both of them.

<h2> $\textbf{Equation I}$ </h2>

$\displaystyle \text{tan(45)} = \frac{h}{x}$

tan(45) = 1, so we can rewrite this equation.

$\displaystyle 1=\frac{h}{x}$

Multiply x to both sides of the equation.

$\displaystyle x = h$

<h2> $\textbf{Equation II}$ </h2>

$\displaystyle \text{tan(30)} = \frac{h}{x+200} }$

Multiply x + 200 to both sides and divide h by tan(30).

$\displaystyle \text{x + 200} = \frac{h}{\text{tan (30)}}$

Subtract 200 from both sides of the equation.

$\displaystyle \text{x} = \frac{h}{\text{tan (30)}} - 200$

Simplify h/tan(30).

$x=\sqrt{3}h - 200$

<h2> $\textbf{Equation I = Equation II}$ </h2>

Take Equation I and Equation II and set them equal to each other.

$h=\sqrt{3}h-200$

Subtract √3 h from both sides of the equation.

$h-\sqrt{3}h=-200$

Factor h from the left side of the equation.

$h(1-\sqrt{3}) =-200$

Divide both sides of the equation by 1 - √3.

$\displaystyle h=\frac{-200}{1-\sqrt{3} }$

Rationalize the denominator by multiplying the numerator and denominator by the conjugate.

$\displaystyle h=\frac{-200}{1-\sqrt{3} } \big{(} \frac{1+\sqrt{3} }{1+\sqrt{3}} \big{)}$
$\displaystyle h=\frac{-200+200\sqrt{3} }{1-3}$
$\displaystyle h =\frac{-200+200\sqrt{3} }{-2}$

Simplify this equation.

$\displaystyle h=100+100\sqrt{3}$
$h=273.20508075$

The height of the lighthouse is about 273 meters.

5 0

3 years ago

Read 2 more answers