The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
Learn more about arithmetic progression here
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200,000,000 that your answer
You have written exactly the same number twice, so neither of them is bigger.
A. define the variables : a = abby's miles, j = james' miles
b. a = j + 4......j = a - 4
c. a + j = 28
a = j + 4
d. (j + 4) + j = 28
2j + 4 = 28
2j = 28 - 4
2j = 24
j = 24/2
j = 12
a = j + 4
a = 12 + 4
a = 16
e. check..
a + j = 28
16 + 12 = 28
28 = 28 (correct)
solution is : abby's miles (a) = 16
james' miles (j) = 12
