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marishachu [46]
3 years ago
10

George earns a salary of $5800 a year. Find his gross wages for his monthly pay period

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

Hello!

If George earns $5800 in a year, he earns $483.33 per month

to get this, do the following

5800 per year

1 year = 12 months

5800 / 12 = 483.3333333

483.3333333 simplified down is 483.33

George earns $483.33 a month

I hope this helps, and have a nice day!

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Which ordered pair is a solution of the equation y equals x minus 3
Rom4ik [11]
Y = x-3

Basically you just need to plug in an x value and solve for y
y = x - 3
y = (4) - 3
y = 1

In this case, the ordered pair of this equation would be (4, 1)

You can do this given any x or y coordinate

Hope this helps 
6 0
3 years ago
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
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What is the estimate of 1374 x 6
timama [110]
Hey it is 1374 x6 8244

7 0
3 years ago
Which sentence explains the correct first step in the solution of this equation? 4(x−3)=94x-3=9?
Dima020 [189]
Do Pemdas
P:Parenthesis
E:Exponent
M:Multiplication
D:Divide
A:Addition
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7 0
3 years ago
Read 2 more answers
Number 13 I don’t get it
Nina [5.8K]
<h3>Answer:  1/2  (choice A)</h3>

===========================================

Explanation:

The two equations given to us are

  • ab = 3
  • ab^2 = 18

Divide the second equation over the first equation and that would lead to b = 6

Notice how the 'a' terms divide to 1 and go away, i.e. cancel out.

The b terms divide to (b^2)/b = b

The right hand side values divide to 18/3 = 6

So that's how we end up with b = 6

-------------------------

Now if b = 6, then we can say,

ab = 3

a*6 = 3

a = 3/6

a = 1/2

Or we could say

ab^2 = 18

a*6^2 = 18

a*36 = 18

a = 18/36

a = 1/2

5 0
3 years ago
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