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Scilla [17]
3 years ago
7

HELP I DONT UNDERSTAND 5 AND 6

Mathematics
1 answer:
Anika [276]3 years ago
7 0
It does represent the function because each out put has only one input
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Three sisters each have a collection of high-heel shoes. Helen has 10 more pairs of shoes than Betty. Natalie has three times as
GaryK [48]

Answer:

Betty has 5 shoes, Helen has 15 shoes, and Natalie has 45 shoes.

Step-by-step explanation:

we can first try to solve this by assigning the sisters different number of shoes. lets give betty 0 shoes, Helen 10 shoes, and Natalie 30 shoes. this does follow the equation, however it does not equal 65.

what if we gave betty 5 shoes, Helen 15 shoes, and Natalie 45 shoes. This does follow the equation, because Helen has 10 more shoes than betty, and Natalie has 3 times more shoes than Helen. 5+15+45=65, So we have our answer!

5 0
3 years ago
Help me ASAP pleasrrrrreee
givi [52]
F(x) is 4 yaaaaaaaaaaaaaaa
3 0
2 years ago
What is the solution set for 2x2 + 15 = -11x?
katovenus [111]

Answer:

<h3>D. {-3, and -2.5}</h3>

Step-by-step explanation:

Using the quadratic equation, you can find the solution to 2x2+15=-11x.

\sf{2x^2+15=-11x}

<u>First, you have to add by 11x from both sides.</u>

\Longrightarrow: \sf{2x^2+15+11x=-11x+11x}

<u>Solve.</u>

2x²+11x+15=0

Use the quadratic formula.

<u>Quadratic formula:</u>

\Longrightarrow: \sf{AX^2+BX+C=0}\\\\\\\Longrightarrow: \sf{x_{1,\:2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}

  • A=2
  • B=11
  • C=15

\sf{x_{1,\:2}=\dfrac{-11\pm \sqrt{11^2-4\cdot \:2\cdot \:15}}{2\cdot \:2}}

<u>Solve.</u>

Use the order of operations.

<u>PEMDAS</u>

  • <u>Parentheses</u>
  • <u>Exponents</u>
  • <u>Multiply</u>
  • <u>Divide</u>
  • <u>Add</u>
  • <u>Subtract</u>

\sf{\sqrt{11^2-4\cdot \:2\cdot \:15}}

<u>Multiply the numbers from left to right.</u>

4*2*15=120

:\Longrightarrow\sf{\sqrt{11^2-120}

<u>Do exponents.</u>

11²=11*11=121

\Longrightarrow: \sf{\sqrt{121-120}

<u>Subtract the numbers from left to right.</u>

121-120=1

\sf{\sqrt{1}}=1

\sf{x_{1,\:2}=\dfrac{-11\pm \:1}{2\cdot \:2}}

\Longrightarrow: \sf{x_1=\dfrac{-11+1}{2\cdot \:2},\:x_2=\dfrac{-11-1}{2\cdot \:2}}

<u>Solve.</u>

\sf{\dfrac{-11+1}{2\cdot \:2}}=\dfrac{-10}{2*2}=\dfrac{-10}{4}=-\dfrac{10}{4}

\sf{\dfrac{-10\div2}{4\div2}=\dfrac{-5}{2}=-\dfrac{5}{2}   }

<u>Divide is another options.</u>

-5/2=-2.5

\sf{\dfrac{-11-1}{2\cdot \:2}}

<u>Solve.</u>

\Longrightarrow: \sf{\dfrac{-11-1}{2\cdot \:2}}=\dfrac{-12}{2*2}=\dfrac{-12\div4}{4\div4}=\dfrac{-3}{1}=-3

<u>Solutions:</u>

\Longrightarrow: \boxed{\sf{-3, \ -2.5}}

  • <u>Therefore, the correct answer is "D. {-3, -2.5}".</u>

I hope this helps. Let me know if you have any questions.

5 0
2 years ago
Matt made model below to help him solve his math problem. Which of the expressions could he have been working on?
atroni [7]
Matt was working on 1/3 × 3/4
hope that helped you have a great day
5 0
3 years ago
The population of a town grew from 20,000 to 28,000. The continuous growth rate is 15%. The equation mc024-1.jpg represents the
Hunter-Best [27]
To calculate the number of years that the population of the town had been growing we proceed as follows;
A=p(1+r/100)^n
where;
A=final population
p=initial population
n=time
r=rate;
thus, substituting the values in the above formula we get:
28000=20000(1+15/100)^n
1.4=(1+0.15)^n
1.4=1.15^n
introducing natural logs we get:
ln1.4=nln1.15
n=(ln1.4)/(ln1.15)
n=2.4
thus;
n=2.4 years
8 0
3 years ago
Read 2 more answers
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