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Rashid [163]
3 years ago
10

25 POINTS FOR ANSWER 7x+5y=19 -7x-2y=-16

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0
Your answer for this problem would be 76-89+ 38, which equals negative 48
You might be interested in
Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
2 years ago
Tell whether (1,6) is a solution of y = x + 7
andrezito [222]

Answer:

no it is not a solution.READ THE WHOLE EXPLANATION! IT WILL HELP WITH THE OTHER PROBLEMS!!!!

Step-by-step explanation:

when something like (1,6) is written consider it as (x,y). in this case, 1 is considered as x, and 6 is considered as y. if you substitute these number for x and x and y, (x =1 and y =6), you'll see that the equation will go from y=x +7, to 6=1+7. Which is not true.

5 0
3 years ago
Read 2 more answers
I need some help with this, I am supposed to solve for x
liq [111]

They are the same measurements, because:

from 10x + 5, first do vertical angle.

then, alternate interior angle,

then vertical angle again,

and another alternate interior angle.

For each vertical and alternate interior angles, the measurements stay the same.


Set them equal to each other, isolate and solve for x.

10x + 5 = 11x - 1

First, isolate the x. Subtract 10x from both sides, and add 1 to both sides

10x (-10x) + 5 (+1) = 11x (-10x) -1 (+1)

Simplify

5 + 1 = 11x - 10x

6 = x

x = 6

6 is your answer for x.

hope this helps

3 0
3 years ago
Solve <br><br>(2)^a−2+(2)^3−a=3​
hoa [83]

Answer: No solution

Step-by-step explanation:

5 0
3 years ago
In AMNO, m = 150 inches, n = 550 inches and o=630 inches. Find the measure of ZO
JulsSmile [24]

Answer:

115.8

Step-by-step explanation:

Delta math

4 0
3 years ago
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