Answer:
Adults =58, Students=92
Step-by-step explanation:
Drag the tiles to the correct boxes to complete the pairs.
1 answer:
Answer:
a 90° clockwise rotation about the origin
a 180° rotation about the origin
a 90° counterclockwise rotation about the origin
Step-by-step explanation:
Transformations are done on a Cartesian Plane, which is the grid with four quadrants. (See picture) Each quadrant is 90°, so two quadrants is 180°.
When you rotate counterclockwise it is like in the picture. When you want to rotate clockwise, it's the other way.
When we rotate 180°, it does not matter if it is counterclockwise or clockwise because the result is the same (both move two quadrants).
We can imagine an example to help us solve the problem. Let's say we are rotating an object <u>starting in </u><u>first quadrant</u><u>.</u> (Upper right quadrant).
<u>Find out which quadrant the object ends up with each instruction:</u>
FROM THE PICTURE:
"a 90° counterclockwise rotation about the origin (Q2) and then a 180° rotation about the origin"
End: Quadrant 4
"a reflection across the x-axis (Q4) and then a reflection across the y-axis"
End: Quadrant 3
"a 90° clockwise rotation about the origin (Q4) and then a rotation 180° about the origin"
End: Quadrant 2
FROM YOUR LIST:
"a 90° counterclockwise rotation about the origin " Quadrant 2
"a 180° rotation about the origin " Quadrant 3
"a 90° clockwise rotation about the origin" Quadrant 4
Match each ending quadrant from your list with the same ending quadrant from the picture.
The order that you should put your list into the boxes is:
a 90° clockwise rotation about the origin
a 180° rotation about the origin
a 90° counterclockwise rotation about the origin
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Answer:
S(t) = a.sin (b.t) + d
a = -1.5, b = (2π/365), d = 3.47
S(t) = -1.5 sin (2πt/365) + 3.47
Step-by-step explanation:
Complete Question is presented in the attached image to this solution.
- Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function S(t) of time t (in days) using a sinusoidal expression of the form
S(t) = a.sin(b.t) + d.
On day t = 0, the stock is at its average value of $3.47 per share, but 91.25 days later, its value is down to its minimum of $1.97.
Find S(t). t should be in radians.
S(t) =
Solution
S(t) = a.sin(b.t) + d.
At t = 0, S(t) = $3.47
S(0) = a.sin(b×0) + d = a.sin 0 + d = 3.47
Sin 0 = 0,
S(t=0) = d = 3.47.
At t = 91.25 days, S(t) = $1.97
But, it is given that T has to be in radians, for t to be in radians, the constant b has to convert t in days to radians.
Hence, b = (2π/365)
S(91.25) = 1.97 = a.sin(b×91.25) + d
d = 3.47 from the first expression
S(t = 91.25) = a.sin (91.25b) + 3.47 = 1.97
1.97 = a.sin (2π×91.25/365) + 3.47
1.97 = a sin (0.5π) + 3.47
Sin 0.5π = 1
1.97 = a + 3.47
a = -1.5
Hence,
S(t) = a.sin (b.t) + d
a = -1.5, b = (2π/365), d = 3.47
S(t) = -1.5 sin (2πt/365) + 3.47
Hope this Helps!!!
