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Aleksandr [31]
3 years ago
9

There are 125 people and three door prizes. How many ways can three door prizes of $50 each be distributed? How many ways can do

or prizes of $5,000, $500 and $50 be distributed?
Mathematics
1 answer:
UkoKoshka [18]3 years ago
3 0

We have been given that there are 125 people and three door prizes.

In the first part we need to figure out how many ways can three door prizes of $50 each be distributed?

Since there are total 125 people and there are three identical door prices, therefore, we need to use combinations for this part.

Hence, the required number of ways are:

_{3}^{125}\textrm{C}=\frac{125!}{122!3!}=\frac{125*124*123}{1*2*3}=317750

In the next part, we need to figure out how many ways can door prizes of $5,000, $500 and $50 be distributed?

Since we have total 125 people and there are three prices of different values, therefore, the required number of ways can be figured out by using permutations.

_{3}^{125}\textrm{P}=\frac{125!}{122!}=125*124*123=1906500


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Part A:

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Part B:

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1                          |||7

6                         |||42

9                         |||63

10                        |||70

Part C:

Tents=x

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2 years ago
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3 0
3 years ago
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All cars can be classified into one of four​ groups: the​ subcompact, the​ compact, the​ midsize, and the​ full-size. There are
Olegator [25]

Answer:

p value = 0.302

Step-by-step explanation:

Given that all cars can be classified into one of four​ groups: the​ subcompact, the​ compact, the​ midsize, and the​ full-size. There are five cars in each group. Head injury data​ (in hic) for the dummies in the​ driver's seat are listed below.

H_0: All cars have same mean values

H_a: atleast two cars have different mean values

(Two tailed anova test)

Anova: Single Factor      

     

SUMMARY      

Groups Count Sum Average Variance  

Subcompact 5 3444 688.8 48502.7  

compact 5 2879 575.8 4582.7  

Midsize 5 2534 506.8 18720.2  

Full size 5 2689 537.8 23905.2  

     

     

ANOVA      

Source of Variation SS df MS            F             P-value F crit

Between Groups 94825 3 31608.33 1.321    0.302           3.24

Within Groups 382843.2 16 23927.7    

     

Total 477668.2 19    

Since p value of 0.302 is greater than 0.05 significance level we accept null hypothesis.

p value = 0.302

6 0
2 years ago
Pls help these are fractions btw.
vichka [17]
<h3><u>S</u><u>olution</u></h3>

1). 1/3 + 1/5 = (5 + 3)/15

= 8/15. Ans.

2).

==> 3/5 - 1/6

= (3×5 - 5)/30

= (15 - 5)/30

= 10/30

= 1/3 Ans.

3).

==> 2/3 ÷ 3/4

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4).

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= 19/24 Ans.

5).

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= (5×2 - 3)/32

= (10-3)/32

= 7/32 Ans.

6 0
3 years ago
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