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Aleksandr [31]
4 years ago
9

There are 125 people and three door prizes. How many ways can three door prizes of $50 each be distributed? How many ways can do

or prizes of $5,000, $500 and $50 be distributed?
Mathematics
1 answer:
UkoKoshka [18]4 years ago
3 0

We have been given that there are 125 people and three door prizes.

In the first part we need to figure out how many ways can three door prizes of $50 each be distributed?

Since there are total 125 people and there are three identical door prices, therefore, we need to use combinations for this part.

Hence, the required number of ways are:

_{3}^{125}\textrm{C}=\frac{125!}{122!3!}=\frac{125*124*123}{1*2*3}=317750

In the next part, we need to figure out how many ways can door prizes of $5,000, $500 and $50 be distributed?

Since we have total 125 people and there are three prices of different values, therefore, the required number of ways can be figured out by using permutations.

_{3}^{125}\textrm{P}=\frac{125!}{122!}=125*124*123=1906500


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Robert run the 100 meter dash in 13.5. later he run same distance in 10.3 seconds. how many seconds less did it take him to run
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Answer:

3.2seconds

Step-by-step explanation:

Step one:

Robert run the 100 meter dash in 13.5 seconds

We are told that he later  run same distance in 10.3 seconds

Required.

The time difference in the first dash and the second

Step two:

The first dash took 13.5 seconds

the second took 10.3 seconds

the difference = 13.5-10.3= 3.2seconds

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3 years ago
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alex41 [277]

Answer:  The last choice is correct. Edna can score 5 times as many points in the next level as in the level she has reached

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x    y

1     5

2   25

3   125

4    625

5    3125

You can see the exponential pattern

For what it's worth, two views of the graph of the equation are attached

The point values are astronomical!

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3 years ago
Equal set is equivalent set but equivalent set not need equal set? why​
nasty-shy [4]
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What is 15/1/20 as a improper fraction
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3 0
4 years ago
Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin
Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

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B=0.13

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O=0.36

As we know that when A and B both are independent that

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The probability that the phenotypes of two randomly selected individuals match:

Here  four case are possible

So

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

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3 years ago
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