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WINSTONCH [101]
3 years ago
15

two objects have the same momentum but different masses Which object the more massive or the less massive object travels faster?

explain your reason​
Physics
2 answers:
suter [353]3 years ago
4 0

Answer: <u>The less massive object</u> because it interacts with the Higgs Field less than the more massive object

Explanation:

There's a simple and very good explanation of this. The Higgs Boson particle is thought to give things mass. And all objects with mass move through the Higgs field interacting with the Higgs particle. The most massive object will interact with these particles more. Therefore gaining more mass. Which in the end makes it move slower. This is actually why objects with mass can't reach the speed of light.

And a good analogy that Neil Degrasse Tyson used was a celebrity entering a bar. People will crowd the celebrity and the celeb will have a difficult time moving around. On the other hand, a simple nobody will have no attention and move around pretty quickly.

Fame = Mass

Ability to move around = How they interact with the Higgs Field

I know this wasn't the answer you were looking for, but it is something to keep in mind when doing future problems in physics

uysha [10]3 years ago
3 0
The the object that has the less mass will travel faster because let’s say for example the first object has the mass of M and the second object has the mass of 2M and if the momentum is equal so that means that we could divide M with M and we would get V1=2V2 (being V1 the velocity of the first mass and V2 the velocity of the second one) I hope I helped you out.
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A long solenoid with 1.65 103 turns per meter and radius 2.00 cm carries an oscillating current I = 6.00 sin 90πt, where I is in
Leno4ka [110]

Answer:

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Explanation:

Given that,

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Current I = 6.00\sin 90\pi t

We need to calculate the induced emf

\epsilon =\mu_{0}nA\dfrac{dI}{dt}

Where, n = number of turns per unit length

A = area of cross section

\dfrac{dI}{dt}=rate of current

Formula of electric field is defined as,

E=\dfrac{\epsilon}{2\pi r}

Where, r = radius

Put the value of emf in equation (I)

E=\dfrac{\mu_{0}nA\dfrac{dI}{dt}}{2\pi r}....(II)

We need to calculate the rate of current

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On differentiating equation (III)

\dfrac{dI}{dt}=90\pi\times6.00\cos(90\pi t)

Now, put the value of rate of current in equation (II)

E=\dfrac{4\pi\times10^{-7}\times1.65\times10^{3}\times\pi\times(2.00\times10^{-2})^2\times90\pi\times6.00\cos(90\pi t)}{2\pi\times 2.00\times10^{-2}}

E=35\cos(90\pi t)\ mV/m

Hence, The  electric field  is 35\cos(90\pi t)\ mV/m

7 0
3 years ago
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When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amp
Paraphin [41]

Answer:

796.18 Hz

Explanation:

Applying,

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f = V'/2πA................ Equation 2

From the question,

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Constant: 3.14.

Substitute these values into equation 2

f = 3.6×10⁻³/( 7.2×10⁻⁷×2×3.14)

f = 796.18 Hz

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