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WINSTONCH [101]
3 years ago
15

two objects have the same momentum but different masses Which object the more massive or the less massive object travels faster?

explain your reason​
Physics
2 answers:
suter [353]3 years ago
4 0

Answer: <u>The less massive object</u> because it interacts with the Higgs Field less than the more massive object

Explanation:

There's a simple and very good explanation of this. The Higgs Boson particle is thought to give things mass. And all objects with mass move through the Higgs field interacting with the Higgs particle. The most massive object will interact with these particles more. Therefore gaining more mass. Which in the end makes it move slower. This is actually why objects with mass can't reach the speed of light.

And a good analogy that Neil Degrasse Tyson used was a celebrity entering a bar. People will crowd the celebrity and the celeb will have a difficult time moving around. On the other hand, a simple nobody will have no attention and move around pretty quickly.

Fame = Mass

Ability to move around = How they interact with the Higgs Field

I know this wasn't the answer you were looking for, but it is something to keep in mind when doing future problems in physics

uysha [10]3 years ago
3 0
The the object that has the less mass will travel faster because let’s say for example the first object has the mass of M and the second object has the mass of 2M and if the momentum is equal so that means that we could divide M with M and we would get V1=2V2 (being V1 the velocity of the first mass and V2 the velocity of the second one) I hope I helped you out.
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A 102 kg football player runs at a speed of 8 m/s to sack the quarterback. What is
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The mass of the quarterback is 61.2 kg.

Explanation:

mass of the football player = m1 = 102 kg

mass of the quarterback = m2 = ?

velocity of the football player = v1 = 8 m/s

According to the law of conservation of momentum:

The total momentum of a system before and after the collision remains constant. Assuming the situation as an isolated system which is not affected by any external factors, we have:

m₁v₁ + m₂v₂ = (m₁+m₂)V

Here, we need to find m₂.

We assume that the quarterback is standing still when he is attacked by the football player so v₂ = 0 m/s

After the collision both of them fall to the ground with a velocity of 5 m/s so V = 5 m/s

102(8) + m2(0) = (102 + m2)(5)\\816 + 0 = (102 + m2)(5)\\816/5 = 102 + m2\\163.2 - 102 = m2\\m2 = 61.2 kg

Keywords: momentum, velocity, law of conservation of momentum

Learn more about Law of Conservation of Momentum from brainly.com/question/7538238

#learnwithBrainly

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