Answer:
Computer A is 1.41 times faster than the Computer B
Explanation:
Assume that number of instruction in the program is 1
Clock time of computer A is 
Clock time of computer B is 
Effective CPI of computer A is 
Effective CPI of computer B is
CPU time of A is

CPU time of B is

Hence Computer A is Faster by 
Computer A is 1.41 times faster than the Computer B
Explanation:
the formula for momentum is denoted by p=mv where p is momentum, m is mass and v is velocity. thus, the velocity before impact would be 0.060 x 30 = 1.8 kg/ms
the second one would just be 0.060 x 20 0.72kg/ms
I'm not 100 percent sure this is correct but yeah
I used rise and run to see where point a lies .
That's kind of an answer you could you right?
Answer:
Written in Python
def energyvector(mass):
c = 2.9979 * 10**8
energy = mass * c ** 2
print(round(energy,2))
Explanation:
This line defines the function
def energyvector(mass):
This line initializes the speed of light
c = 2.9979 * 10**8
This line calculates the corresponding energy
energy = mass * c ** 2
This line prints the calculated energy
print(round(energy,2))
Answer:
0.434 m
Explanation:
We are given that
Mass per unit length=
1 kg=1000 g
Tension=350 N
Fundamental frequency=f=440 Hz
We have to find the length you should make it.
We know that

Using the formula

l=0.434 m
Hence, you should make it 0.434 m long.