The height of the ball above the ground is 38.45 m
First we will calculate the velocity of the ball when it touch the ground by using first equation of motion
v=u+gt
v=0+9.81×2.8
v=27.468 m/s
now the height of the ground can be calculated by the formula
v=√2gh
27.468=√2×9.81×h
h=38.45 m
They all have segmented limbs, a hard exoskeleton, a pair of antennae and a segmented body.
The bouncing person because the bounce helped him survive
Answer:
d= 794.4 cmExplanation:
Given that
Speed ,V= 286 km/h

V=79.44 m/s
Given that time ,t= 100 ms
t= 0.1 s
We know that ( if acceleration is zero)
Distance = Speed x time
d= V t
Now by putting the values in the above equation
d = 79.44 x 0.1 m
d= 7.944 m
We know that 1 m = 100 cm
d= 794.4 cm
This is honestly not something I’ve learned. The answer is something I don’t know.