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3 years ago

Please help with #7 thanks

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

6 0

The expression would be 45 + 3w
you already have 45 so that will be added and 3 w is for 3 dollars per week

4 weeks: 45 + 3x4= $57
10 weeks: 45 + 3x10= $75
20 weeks: 45 + 3x20= $105

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CAN SOMEONE HELP PLZ ASAP!

Anna35 [415]

Answer:

A= 1/8
B= 3/8

Solution:
Count how many lines there are except the Line on zero. This number is 8 and will be the denominator. Then count the number of lines to the one you’re looking at

8 0

3 years ago

Two containers hold several balls. Once a second, one of the balls is chosen at random and switched to the other container. Afte

natka813 [3]

Answer:

(a) 8 balls

(b) 4 balls

Step-by-step explanation:

Let

$N \to$ Number of balls

For a box, the probability that there are N balls in it is:

$Pr = 0.5^N$

For 2 boxes, it is:

$Pr = 2 * 0.5^N$

From the question, we have:

$\frac{80}{10000} \to$ Favorable outcome

To solve for N, we have:

$2 * 0.5^N = \frac{80}{10000}$

$2 * 0.5^N = 0.008$

Divide both sides by 2

$0.5^N = 0.004$

Take log of both sides

$\log(0.5^N) = \log(0.004)$

Apply law of logarithm

$N\log(0.5) = \log(0.004)$

Make N the subject

$N = \frac{\log(0.004)}{\log(0.5)}$

$N =7.966$

Approximate

$N = 8$

Solving (b): Balls in one of the two boxes.

Here, we assume that each ball will have almost the same number of balls at a given instance;

Hence, we have:

$Balls \approx \frac{N}{2}$

$Balls \approx \frac{8}{2}$

$Balls \approx 4$

4 balls in each box

6 0

3 years ago

I really need help with this question, can you help?

Varvara68 [4.7K]

Answer:

sure! whats the question?

Step-by-step explanation:

6 0

3 years ago

Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360°

vodka [1.7K]

$2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or} ~~u =\dfrac{-4}{4} =-1\\\\$

$\implies \tan x = \dfrac 12 ~~ \text{or} ~~ \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\$

$x=\tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,} ~~x=\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\$

$\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]$

4 0

2 years ago

Solve by factoring. m^2+6m+5=0

alina1380 [7]

Answer:

-1 and -5

Step-by-step explanation:

m^2 + 6m + 5 = 0 is factored to: (m + 1)(m + 5) = 0.

The zero product property states that one of the represented parenthesis must equal zero to satisfy the right side of the equation.

(m + 1) = 0

(-1 + 1) = 0

This means that one of the values for m is -1.

(m + 5) = 0

(-5 + 5) = 0

This means that one of the values for m is -5.

Moreover, the value of m by factoring is -1 and -5

3 0

3 years ago