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3 years ago

How old am I if 300 reduced by 2 times my age Is 114

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

8 0

The formula would be (a-c)/b=x and when you plug the formula in x=93

vova2212 [387]3 years ago

6 0

The answer is 93 years old.

You might be interested in

The probability of rolling two dice at the same time and getting a 4 with either die or the sum of the dice is 6

aleksklad [387]

Answer:

Suppose that the first die we roll comes up as a 1. The other die roll could be a 1, 2, 3, 4, 5, or 6. Now suppose that the first die is a 2. The other die roll again could be a 1, 2, 3, 4, 5, or 6. We have already found 12 potential outcomes, and have yet to exhaust all of the possibilities of the first die. But with a second dice, there will be 24 different possibilities.

Step-by-step explanation:

1 2 3 4 5 6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

4 0

4 years ago

What is the value of x? 5x+3/-2=4 HELP HELP HELP

Tems11 [23]

Answer:

5x+3=4*-2

5x+3= -8

5x=-8-3

x= -11/5

3 0

3 years ago

What is the asymptote of the graph of f(x)=5x−1?

Marina86 [1]

The asymptotes of the graph of $f(x) = \frac{5}{x - 1}$ are as follows:

Vertical: x = 1.

Horizontal: y = 0.

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$f(x) = \frac{5}{x - 1}$

For the vertical asymptote, we have that:

$x - 1 = 0 \rightarrow x = 1$ .

For the horizontal asymptote, we have that:

$y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0$ .

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

3 0

2 years ago

You are told that a third powered polynomial has zeroes at -1, 2, 5.

vichka [17]

Answer:

a) factors of polynomial are: (x+1)(x-2)(x-5)

b) the required polynomial in standard form is: $\mathbf{x^3-6x^2+3x+10}$

Step-by-step explanation:

The polynomial has zeros at -1,2,5

Part A) Write the three factors of the polynomial

we have x=-1, x=2 and x=5 as zeros of polynomial

so factors will be:

(x+1)=0, (x-2)=0, (x-5)=0

So, factors of polynomial are: (x+1)(x-2)(x-5)

Part B) Write the polynomial in standard form

For finding polynomial, we will multiply all the factors i.e

(x+1)(x-2)(x-5)

$(x+1)(x-2)(x-5)\\=(x(x-2)+1(x-2))(x-5)\\=(x^2-2x+x-2)(x-5)\\=(x^2-x-2)(x-5)\\=x(x^2-x-2)-5(x^2-x-2)\\=x^3-x^2-2x-5x^2+5x+10\\=x^3-x^2-5x^2+5x-2x+10\\=x^3-6x^2+3x+10$

So, the required polynomial in standard form is: $x^3-6x^2+3x+10$

7 0

3 years ago

Help me with my math pls :)

MrMuchimi

Answer:

4(x-8)=-32+4: x=1

2(x-2)=-3-2x: x1/4

3+5x=5(x+2)-7: x=0

8x+38=-3(-6-4x) x=5

Step-by-step explanation:

4(x-8)=-32+4

add subtract the numbers

-32+4=-28

4(x-8)=-28

Divide both sides by 4

$\frac{4(x-8)}{4}=\frac{-28}{4}$

Simplify

x-8=-7

Add 8 on both sides

x+8-8=-7+8

Simplify

x=1

2(x-2)=-3-2x

Expand 2(x-2)
apply distributive law: a(b-c)=ab-ac

a=2 b=x c=2

=2x-2·2

multiply the numbers

2·2=4

=2x-4

2x-4=-3x-2

Add 4 to both sides

2x-4+4=-3-2x+4

simplify

2x=-2x+1

Add 2x on both sides

2x+2x=2x+1+2x

Simplify

4x=1

Divide by 4 on both sides

4x÷4=1÷4

Simplify

x=1/4

3+5x=5(x+2)-7

We move all terms to the left:

3+5x-(5(x+2)-7)=0

We calculate terms in parentheses: -(5(x+2)-7), so:

5(x+2)-7

We multiply parentheses

5x+10-7

We add all the numbers together, and all the variables

5x+3

Back to the equation:

-(5x+3)

We get rid of parentheses

5x-5x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

8x+38=-3(-6-4x)

Simplifying

8x + 38 = -3(-6 + -4x)

Reorder the terms:

38 + 8x = -3(-6 + -4x)

38 + 8x = (-6 * -3 + -4x * -3)

38 + 8x = (18 + 12x)

Solving

38 + 8x = 18 + 12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12x' to each side of the equation.

38 + 8x + -12x = 18 + 12x + -12x

Combine like terms: 8x + -12x = -4x

38 + -4x = 18 + 12x + -12x

Combine like terms: 12x + -12x = 0

38 + -4x = 18 + 0

38 + -4x = 18

Add '-38' to each side of the equation.

38 + -38 + -4x = 18 + -38

Combine like terms: 38 + -38 = 0

0 + -4x = 18 + -38

-4x = 18 + -38

Combine like terms: 18 + -38 = -20

-4x = -20

Divide each side by '-4'.

x = 5

Simplifying

x = 5

Hope this helps

4 0

3 years ago