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sveticcg [70]
3 years ago
7

How many years does it take for an annuity of $ 1,000 to grow to $ 20,000, assuming k = 7%?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
8 0
For an annual deposit of A=$1000 (at the end of the year) at an annual interest rate of i=7% compounded yearly, the future value 
F=\frac{A((1+i)^n-1)}{i}   where n=number of years
=>
20000=\frac{1000((1+.07)^n-1)}{.07}
on simplification
1.4=(1.07)^n-1
(1.07)^n=2.4
take logs and solve for n
n=log(2.4)/log(1.07)
n=12.939  years, to the nearest 0.001 year

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choli [55]

Answer:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

Step-by-step explanation:

\mu=35\\n=23\\\=x=33\\s=5\\\alpha=0.1

1. Null and alternative hypothesis

H_{0}:\mu=35\\H_{1}:\mu

2. Significance level

\alpha=0.1\\1-\alpha=0.99

Freedom degrees is given by:

v=n-1\\v=23-1=22

For a sgnificance level of 0,01 and 22 freedom degrees,  t-student distribution value is:

t_{0.01;23}=-2. 5083

3. Test statistic

t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }

t=\frac{33-35}{\frac{5}{\sqrt{23} } }

t=-1,918

In this case, we have an one left tailed analysis, it means that null hypothesis is rejected if t

-1.918>-2.5083

Conclusion:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

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