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kumpel [21]
4 years ago
14

One cup equals approximately 236 ml. Approximately how many ml are there in one gallon

Mathematics
1 answer:
GREYUIT [131]4 years ago
5 0

Answer:

<u>Approximately there are 3,785.6 milliliters in one gallon </u>

Step-by-step explanation:

Let's find out how many milliliters are there in one gallon.

1 US Cup = 236.6 ml (actual equivalence)

Let's recall that:

16 US Cups = 1 US Gallon

Therefore,

1 US Gallon = 16 * 236.6 ml

1 US Gallon = 3,785.6 ml

<u>Approximately there are 3,785.6 milliliters in one gallon</u>

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Type the missing number in this sequence:<br> -2,<br><br> -50,<br> -250, <br> -1,250, <br> -6,250
bazaltina [42]

Answer:

the next is -2 × 5 = - 10

Step-by-step explanation:

the sequence is times 5

5 0
3 years ago
You have five seasons of your favorite TV show on DVD. If you randomly select two of them from a shelf, what is the probability
d1i1m1o1n [39]
1/5 since your choosing 1 dvd out of 5 

and then assuming you DONT put season one back on the shelf you would then have the probablity of 1/4 because you are again choosing 1 dvd out of now 4
8 0
3 years ago
I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

4 0
4 years ago
The equation below describes a proportional relationship between x and y. What is the constant of? proportionality? y equals thr
lilavasa [31]

Answer:

The given equation is

          y =\frac{3}{7} x

→ \frac{y}{x} = \frac{3}{7}

reciprocating both sides, we get

→ \frac{x}{y}  =  \frac{7}{3} ............(1)  

→ Here x and y are Directly proportional to each other.

which means ,

→ x =  k y , where k is constant of proportionality.

Or , \frac{x}{y} = k  ............................(2)

Equating (1) and (2),

k = \frac {7}{3}  




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