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Alexandra [31]
3 years ago
11

Find the coordinates of the midpoint of the segment whose endpoints are H(6, 4) and K(2, 8).

Mathematics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

(4, 6)

Step-by-step explanation:

Midpoint Formula ( X₁ + X₂/2 , Y₁ + Y₂/2 )

Substitute for the x- coordinate = (6+2 / 2)

* add 6 and 2 which gives you 8.

*then divide 8 by 2

8/2=4

Substitute for the y-coordinate = (4+8 / 2)

* add 4 and 8 which gives you 12.

* then divide 12 by 2

12/2=6

Answer: (4,6)

Serhud [2]3 years ago
3 0
The midpoint formula is ( x + x / 2, y + y / 2) 
so....
6+ 2 = 8 / 2 = 4
4 + 8 = 12 / 2 = 6
the midpoint is (4, 6)
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4ft

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2 years ago
The functions f (x) = 1/2x-3 and g(x) = -2x+ 2 intersect<br> at x = -2. True or false?
Norma-Jean [14]

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Answer:

  False

Step-by-step explanation:

f(-2) = (1/2)(-2) -3 = -1 -3 = -4

g(-2) = -2(-2) +2 = 4 +2 = 6

The function values are not the same at x=-2, so the graphs do not intersect there.

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The graphs intersect at x=2.

4 0
3 years ago
What is the value for ƒ(x) = 42x - 100 when x = 2 ?
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3 0
3 years ago
I need to know how to solve for the value of x
dimulka [17.4K]
Hey Katie

4^2x+3 = 1
We need to solve for x

log(4^2x+3) = log (1)
Now take log of
(2x +3) * log (4) = log (1)
2x + 3 = log(1)/log(4)
2x + 3 = 0
2x = 0 - 3
2x = -3
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I hope that's help ! 

8 0
3 years ago
Determine which equation is parallel to the line JK and which is perpendicular to like JK
sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and y = - \frac{1}{m}x + b will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as  

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be  

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation  

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ n = - \frac{1}{m}

Therefore, the equation of a straight line which is perpendicular to equation (1) will be y = - \frac{1}{m}x + b where b is any real constant. (Answer)

3 0
3 years ago
Read 2 more answers
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