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Sladkaya [172]
3 years ago
9

Give an example of a rational function that has a horizontal asymptote of y = 2/9.

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0
Note that the graph of the function \displaystyle{ f(x)= \frac{1}{x} has 2 asymptotes:

The horizontal asymptote x=0, 

and the vertical asymptote y=0, as shown in the first picture.


Adding 2/9 to this function, creating \displaystyle{ g(x)= \frac{1}{x}+\frac{2}{9}, shifts the first graph 2/9 units up. It also shifts the horizontal asymptote y=0 to t=2/9.

We can express the function as \displaystyle{ \frac{1}{x}+ \frac{2}{9}= \frac{9}{9x}+ \frac{2x}{9x}= \frac{2x+9}{9x}.


Answer: \displaystyle{ \frac{2x+9}{9x}


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The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. I
Firdavs [7]

The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).

<h3>How to analyze quadratic equations</h3>

In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:

g(x) = C · (x - h)² - k     (1)

Where:

  • (h, k) - Vertex coordinates
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By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.

x = 2

g(2) = (2 - 5)² + 1

g(2) = 10

x = 8

g(8) = (8 - 5)² + 1

g(8) = 10

The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).

To learn more on parabolae: brainly.com/question/21685473

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7 0
2 years ago
If G(s) is the inverse of S(g) , and G(2) =16 then s(16) = 2 true or false?
lina2011 [118]
If f(x) is the inverse of g(x) then if f(a)=b then g(b)=a

so if G(s) is the inverse of S(g) then if G(2)=16 then S(16)=2, true

yes, it's true

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