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schepotkina [342]
3 years ago
14

1. Find an algebraic representation for an exponential function if it is known that f(x + 1) = 4.f(x)

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

f(x)=4^{x-1} is the algebraic representation for an exponential function

Step-by-step explanation:

Given:

f(x + 1) = 4.f(x)

f(3) = 16

To Find:

Algebraic representation for an exponential function=?

Solution:

From the formula f(x+n) = 4^n f(x)

when n= 1, x= 3

f(3+1)= 4(1)f(3)

f(4)= 4f(3)

Substituting the value of f(3)

f(4)= 4f(3)

f(4)= 4 x 16  

f(4)= 64

f(4)=4^2

f (5) = 4^2 x 16

f (5) = 4^2 x  4^2

f(5)= 4^4

Similarly,

F(6) = 4^5

Hence, f(x)=4^{x-1}

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This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

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Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

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                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

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   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

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