What is the value of 4|3-(-8)|+11

sweet [91]

So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.

A: $\sqrt[4]{1.6*10^1^1} = 632.455...$ This is a decimal therefore not an integer.

B: $\sqrt[4]{1.6*10^1^2} =1124.682...$ Again a decimal, therefore not an integer.

C: $\sqrt[4]{1.6*10^1^3} =2000$ This is a whole number, so it is an integer.

D: $\sqrt[4]{1.6*10^1^4} =3556.558...$ Decimal, therefore not an integer

E: $\sqrt[4]{1.6*10^1^5} =6324.555...$ Again a decimal, not an integer.

The only one that gives an integer when put to the 4th root is C, therefore:

$1.6*10^1^3$ could be A^4, as the 4th root of it is an integer.

5 0

3 years ago

What is the area of the figure? 118 in 2 48 in 2 128 in 2 108 in 2

cricket20 [7]

The answer Is D! 108 In 2.

8 0

3 years ago

Find the slope of the line.

andrey2020 [161]

Answer:

-1

Step-by-step explanation:

To find the slope of a line, we can do rise over run, or y/x.

r/r = 1/1 = 1

But as you can see, the line is going down which means it's decreasing, which means that it has a negative slope

slope = -1

Hope this helped a little!

Have a supercalifragilisticexpialidocious day!

5 0

3 years ago

2x^3-x^2-3x=210 the answer is 5 but I want to know why.

mel-nik [20]

Answer:

$x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}$

Step-by-step explanation:

1) Move all terms to one side.

$2x^{3} -x^{2} -3x-210=0$

2) Factor $2{x}^{3}-{x}^{2}-3x-210$ using Polynomial Division.

1 - Factor the following.

$2x^{3} -x^{2} -3x-210$

2 - First, find all factors of the constant term 210.

$1,2,3,4,5,6,7,10,14,15,21,30,35,42,70,105,210$

3) Try each factor above using the Remainder Theorem.

Substitute 1 into x. Since the result is not 0, x-1 is not a factor..

$2*1^{3} -1^{2} -3*1-210=-212$

Substitute -1 into x. Since the result is not 0, x+1 is not a factor..

$2(-1)^{3} -(-1)^{2} -3*-1-210=-210$

Substitute 2 into x. Since the result is not 0, x-2 is not a factor..

$2*2^{3} -2^{2} -3*2-210=-204$

Substitute -2 into x. Since the result is not 0, x+2 is not a factor..

$2{(-2)}^{3}-{(-2)}^{2}-3\times -2-210 = -224$

Substitute 3 into x. Since the result is not 0, x-3 is not a factor..

$2\times {3}^{3}-{3}^{2}-3\times 3-210 = -174$

Substitute -3 into x. Since the result is not 0, x+3 is not a factor..

$2{(-3)}^{3}-{(-3)}^{2}-3\times -3-210 = -264$

Substitute 5 into x. Since the result is 0, x-5 is a factor..

$2\times {5}^{3}-{5}^{2}-3\times 5-210 =0$

------------------------------------------------------------------------------------------

⇒ $x-5$

4) Polynomial Division: Divide $2{x}^{3}-{x}^{2}-3x-210$ by $x-5$ .

$2x^{2}$ $9x$ $42$

-------------------------------------------------------------------------

$x-5$ | $2x^{3}$ $-x^{2}$ $-3x$ $-210$

$2x^{3}$ $-10x^{2}$

-----------------------------------------------------------------------

$9x^{2}$ $-3x$ $-210$

--------------------------------------------------------------------------

$42x$ $-210$

-------------------------------------------------------------------------

5) Rewrite the expression using the above.

$2x^2+9x+42$

$(2x^2+9x+42)(x-5)=0$

3) Solve for $x.$

$x=5$

4) Use the Quadratic Formula.

1 - In general, given $a{x}^{2}+bx+c=0$ , there exists two solutions where:

$x=\frac{-b+\sqrt{b^{2} -4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}$

2 - In this case, $a=2,b=9$ and $c = 42.$

$x=\frac{-9+\sqrt{9^2*-4*2*42} }{2*2} ,\frac{-9-\sqrt{9^2-4*2*42} }{2*2}$

3 - Simplify.

$x=\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}$

5) Collect all solutions from the previous steps.

$x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}$

4 0

2 years ago

Read 2 more answers

Which graph contains the points of intersection

timama [110]

Answer:

graph A

Step-by-step explanation:

if you use the substitution method is graph A

4 0

3 years ago