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ASHA 777 [7]
3 years ago
13

((Image Included))

Mathematics
2 answers:
kvasek [131]3 years ago
7 0

Answer: 204.12 inches

Step-by-step explanation:

We can find the lengths of the unknown sides by applying these identities:

tan\alpha=\frac{opposite}{adjacent}\\\\sin\alpha=\frac{opposite}{hypotenuse}

Observe the image attached. To find "a" we need to substitute the following values into tan\alpha=\frac{opposite}{adjacent}:

\alpha=30\°\\opposite=x=27\\adjacent=a

And solve for "a":

tan(30\°)=\frac{27}{a}\\\\a=\frac{27}{tan(30\°)}\\\\a=46.76\ inches

To find "b" we need to substitute the following values into sin\alpha=\frac{opposite}{hypotenuse}:

\alpha=30\°\\opposite=x=27\\hypotenuse=b

And solve for "b":

sin(30\°)=\frac{27}{b}\\\\b=\frac{27}{sin(30\°)}\\\\b=54 inches

 To find "c" we need to substitute the following values into sin\theta=\frac{opposite}{hypotenuse}:

\theta=45\°\\opposite=x=27\\hypotenuse=c

And solve for "c":

sin(45\°)=\frac{27}{c}\\\\c=\frac{27}{sin(45\°)}\\\\c=38.18 inches

Since the triangle on the left is Isosceles, then:

d=c= 38.18\ inches\\\\

Therefore, the perimeter is:

P=(46.76+54+2(38.18)+27)\ inches=204.12\ inches

Bas_tet [7]3 years ago
6 0

Answer:

=204.13 inches.

Step-by-step explanation:

Using the side x, we can use sine to find the hypotenuse of the triangle with the angle marked 30°.

Sin 30 =x/hypotenuse.

sin 30 = 27/hyp

hyp= 27/sin 30

=54 inches

We can also find the adjacent as follows.

Cos 30 = adjacent/ 54

Adjacent= 54 cos 30

=46.77 inches

Using the angles marked 45 we can find the hypotenuse of the isosceles triangle.

sin 45= x/hypotenuse

sin 45 =27/hypotenuse

hypotenuse = 27/sin 45

=38.18 inches

The hypotenuse of both the triangles making the isosceles triangle are 38.18 inches long.

Perimeter = 54+ 46.77+27+ 38.18+38.18

=204.13 inches.

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Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and
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Answer:

A. g'(3)=-\frac{1}{2}

Step-by-step explanation:

We have been given that f be a differentiable function such thatf(3)=15, f(6)=3, f'(3)= -8, and f'(6)= -2. The function g is differentiable and g(x)= f^{-1} (x) for all x.

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Upon taking derivative of both sides of our equation, we will get:

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