Commutative Property of Addition
Let

be the identity matrix. Then pick whatever matrix you like for

.
Easy peasy
the bit where it says
D={something}
those are the numbers you should input for x to get y values
3.
first solve for y to make life easier
-3x-5y=20
times -1
3x+5y=-20
minus 3x both sides
5y=-3x-20
divide both sides by 5
y=-3/5x-4
sub value of the domain
x=-10
y=-3/5(-10)-4
y=6-4
y=2
a point is (-10,2)
x=-5
y=-3/5(-5)-4
y=3-4
y=-1
(-5,-1) is another
x=0
y=-3/5(0)-4
y=-4
(0,-4) is another
x=5
y=-3/5(5)-4
y=-3-4
y=-7
(5,-7)
points are (-10,2), (-5,-1), (0,-4), (5,-7)
4.
input
x=-2
y=(-2)^2-3
y=4-3
y=1
(-2,1)
x=-1
y=(-1)^2-3
y=1-3
y=-2
(-1,-2)
x=0
y=(0)^2-3
y=-3
(0,-3)
x=1
y=(1)^2-3
y=1-3
y=-3
(1,-3)
x=2
y=(2)^2-3
y=4-3
y=1
(2,1)
the points are (-2,1), (-1,-2), (0,-3), (1,-2), (-2,1)
see graph below
Answer:
p=0.07
Step-by-step explanation:
7p+15.89=19.32
19.32-15.89=3.43
3.43/7= 0.07
p=0.07
Answer:
Javier flew his kite for 4 more hours on Wednesday and Thursday than Monday and Tuesday.
Step-by-step explanation:
He flew his kite for 4 hours on Wednesday and 3 hours on Thursday.
4 + 3 = 7.
Previously, on Monday, he flew his kite for 1 hour, and on Tuesday, he flew his kite for 2 hours.
1 + 2 = 3.
7 - 3 = 4.