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3 years ago

Find the midpoint of the line segment whose endpoint are (2.6,5.1) and (3,4.7)

Mathematics

1 answer:

zalisa [80]3 years ago

7 0

$A(2.5, 5.1), B(3, 4.7)$

$M(\frac{2.5+3}{2}, \frac{5.1+4.7}{2})$

$M(\frac{5.5}{2}, \frac{9.8}{2})$

$\boxed{M(2.75, 4.9)}$

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What is the value of x?

Kamila [148]

Answer:

x = 3

Step-by-step explanation:

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3 years ago

The midpoint of RS¯¯¯¯¯¯¯ is M. Use the given endpoint R(23, 14) and midpoint M(13, 8) to find the coordinates of the other endp

Oksanka [162]

The coordinates of other endpoint S is (3, 2)

<h3>Solution:</h3>

Given that midpoint of RS is M

Given endpoint R(23, 14) and midpoint M(13, 8)

To find: coordinates of the other endpoint S

The formula for midpoint is given as:

For a line containing containing two points $(x_1, y_1)$ and $(x_2, y_2)$ midpoint is given as:

$m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here in this problem,

m(x, y) = (13, 8)

$(x_1, y_1) = (23, 14)\\\\(x_2, y_2) = ?$

Substituting the given values in above formula, we get

$(13,8)=\left(\frac{23+x_{2}}{2}, \frac{14+y_{2}}{2}\right)$

Comparing both the sides we get,

$\begin{aligned}&13=\frac{23+x_{2}}{2} \text { and } 8=\frac{14+y_{2}}{2}\\\\&26=23+x_{2} \text { and } 16=14+y_{2}\\\\&x_{2}=3 \text { and } y_{2}=2\end{aligned}$

Thus the coordinates of other endpoint S is (3, 2)

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3 years ago

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Step-by-step explanation:

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3 years ago

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german

We have that
scale factor=3

we know that
[volume new cube]=[scale factor]³*[volume original cube]
[volume new cube]=[3]³*[volume original cube]-----> 27*[volume original cube]

the answer is
the volume increases by a factor of 27

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3 years ago

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kotykmax [81]

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