https://youtu.be/QnydfcNVJoQ
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have an arithmetic sequence here....to find the common difference, subtract the first term from the second term. 13 - 3 = 10...so basically, ur adding 10 to each number to get to the next number.
before we find s5, we r going to find a5...because we need a5 to use in the sum formula.....a5 is the fifth term, and it is 43
sn = (n (a1 + a5) / 2
s5 = (5 (3 + 43) / 2
s5 = (5 (46)) / 2
s5 = 230/2
s5 = 115 <===
or, for this particular problem, s5 is the sum of the first 5 terms.
3 + 13 + 23 + 33 + 43 = 115.....u can do it this way for s5...but if u were asked to find s20, I suggest using the formula.
If there are 18 students every one of the will pair up with 17 other students throughout the year so the total amount of pairs that can be made is 18x17=306 but since it’s not important if student A is paired with student B or student B with student A we should divide the total amount of pairs by two- 306:2=153 so in total there will be 153 projects finished
Answer:
x = -12
Step-by-step explanation:
-2.5(x-4)=-3x+4
Distribute
-2.5x +10 = -3x +4
Add 3x to each side
-2.5x+10 +3x = -3x+4+3x
.5x +10 = 4
Subtract 10 from each side
.5x+10-10=4-10
.5x = -6
Divide by .5
.5x/.5 = -6/.5
x = -12
Answer:
Options B and D are true.
Step-by-step explanation:
See the diagram attached.
Line a and b are parallel and line c is not parallel to them.
There is a transverse line and this line forms the angles 1 to 12.
Now, option A gives ∠ 8 + ∠ 10 = 180° which can not be true as line c is not parallel to line b.
Option B gives ∠4 + ∠ 6 = 180° which is true because line a is parallel to line b and ∠ 4 and ∠ 6 are interior supplementary angles.
Option C gives ∠ 1 + ∠ 11 = 180° which can not be true as line c is not parallel to line a.
Option D gives ∠3 + ∠ 5 = 180° which is true because line a is parallel to line b and ∠ 3 and ∠ 5 are interior supplementary angles.
Therefore, options B and D are true. (Answer)
