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Ede4ka [16]
3 years ago
7

Number one is the question I need help on!

Chemistry
1 answer:
Darina [25.2K]3 years ago
7 0

Apply unitary method,

A day = 24 × 60 minutes

So,

Please refer to the attachment above.

Hope this will help you. 

If you like my answer. Please mark it as brainliest  And  Be my follower if possible.

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List three properties of metal that nonmetals typically DO NOT have
finlep [7]
-They can conduct heat
-They can conduct electricity
-They are typically stronger than non metals
Hope this helps, have a nice day! :)
7 0
3 years ago
Read 2 more answers
ASAP! What is the total number of electrons that can occupy the f sublevel? a 2 electrons b 6 electrons c 10 electrons d 14 elec
vaieri [72.5K]

Answer:

14 electrons

Explanation:

The total number of electrons that can occupy the f sublevel is 14.

The d sublevel can have 10 electrons.

The p sublevel can have 6 electrons

The s sublevel can have 2 electrons.

4 0
4 years ago
Read 2 more answers
How much of a 0.250 M lithium hydroxide is required to neutralize 20.0 mL of 0.345M chlorous acid?
Bumek [7]

Answer:

27.6mL of LiOH 0.250M

Explanation:

The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

LiOH + HClO₂ → LiClO₂ + H₂O

<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

<h3>27.6mL of LiOH 0.250M</h3>
6 0
3 years ago
What two reactants are necessary in order for a hydrocarbon combustion reaction to take place?
VladimirAG [237]

Answer:

A hydrocarbon and oxygen

Explanation:

hydrocarbon is being burned, and oxygen is necessary to burn things

6 0
3 years ago
A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation
qaws [65]

Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its <em>wavelength</em> and <em>temperature</em> is given by Wien's displacement law.

\lambda_{max}=\frac{b}{T}

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K  }{0.21m} =0.014K

8 0
4 years ago
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