Answer:
London dispersion forces
Explanation:
There are different forces of attraction that helps to hold atoms or Molecules of a particular substance together. Some of the forces of attraction are ionic/ electrovalent bond, covalent bond, vander waals forces of attraction and so on.
Under the vander waals forces of attraction we have what is known as the London dispersion forces. This force of attraction is a very weak and it is commonly found in the atoms of noble gases.
The intermolecular force of attraction in which we are talking about that is london dispersion forces is formed as a result of the formation of non-polar dipoles which are not permanent.
Answer: <span>Arachidonic Acid and PGE</span>₁<span> are both carboxylic acids with
<u>Twenty Carbon</u> atoms. The differences are that Arachidonic acid contains
<u>Four <em>cis</em> Double Bonds</u> and no other functional groups, whereas PGE</span>₁<span> has
<u>One <em>Trans</em> Double Bond, Two Hydroxyl and One Ketone Functional Groups.</u>. In addition, a part of the PGE</span>₁<span> chain forms a
<u>Five Membered Ring</u>.
Structures of Both Arachidonic Acid and PGE</span>₁ are shown Below,
First blank is: Half-Life
Second Blank is: decay into its products
Answer:
0.7g of HCl
Explanation:
First, let us write a balanced equation for the reaction between HCl and Al(OH)3.
This is illustrated below:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
Next, let us obtain the masses of Al(OH)3 and HCl that reacted together according to the equation. This can be achieved as shown below:
Molar Mass of Al(OH)3 = 27 + 3(16+1)
= 27 + 3(17) = 27 + 51 = 78g/mol.
Molar Mass of HCl = 1 + 35.5 = 36.5g/mol
Mass of HCl from the balanced equation = 3 x 36.5 = 109.5g
Now we can obtain the mass of HCl that would react with 0.5g of Al(OH)3. This can be achieved as follow:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
From the equation above,
78g of Al(OH)3 reacted with 109.5g of HCl.
Therefore, 0.5g of Al(OH)3 will react with = (0.5 x 109.5)/78 = 0.7g of HCl
Answer:
24 atm is the total pressure exerted by the gases
Explanation:
We propose this situation:
In a vessel, we have 4 gases (for example, hydrogen, Xe, methane and chlorine)
Each of the gases has the same pressure:
6 atm → hydrogen
6 atm → xenon
6 atm → methane
6 atm → chlorine
To determine the total pressure, we sum all of them:
Partial pressure H₂ + Partial pressure Xe + Partial pressure CH₄ + Partial pressure Cl₂ = Total P
6 atm + 6 atm + 6 atm + 6 atm = 24atm
