Answer:
Value of 
is 0.090.
Explanation:
Initial molarity of 
= 
= 0.0700 M
Construct an ICE table corresponding to the combustion reaction of carbon to determine
I (M): - 0.0700 0
C (M): - -x +2x
E (M): - 0.0700-x 2x
So, ![K_{c}=\frac{[CO]^{2}}{[O_{2}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BCO%5D%5E%7B2%7D%7D%7B%5BO_%7B2%7D%5D%7D)
, where [CO] and ![[O_{2}]](https://tex.z-dn.net/?f=%5BO_%7B2%7D%5D)
represents equilibrium concentration of CO and respectively.
Here, ![[CO]=2x=0.060](https://tex.z-dn.net/?f=%5BCO%5D%3D2x%3D0.060)
⇒x = 0.030
So, = 0.0700-x = (0.0700-0.030) = 0.040
Hence, 
A)→ Haze surrounding a nucleus
B)→ Created by solar wind.
C)→ Hypothetical sphere around the solar system
The specific heat in, J /g °C of copper is 0.386J/g°C
HOW TO CALCULATE SPECIFIC HEAT CAPACITY OF A SUBSTANCE:
- The specific capacity of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or released (J)
m = mass of substance (g)
∆T = change in temperature (°C)
c = specific heat capacity (J/g°C)
For a colorimeter, the following equation applies:
m.c.∆T (water) = - m.c.∆T (metal)
m = 50g
c = 4.184 J/g°C
∆T = 29.2 - 26°C = 3.2°C
m = 70g
c = ?
∆T = 29.2 - 54°C = -24.8°C
m.c.∆T (water) = - m.c.∆T (metal)
50 × 4.184 × 3.2 = -(70 × c × -24.8)
669.44 = 1736c
c = 669.44 ÷ 1736
c = 0.386J/g°C
Therefore, the specific heat in, J /g °C of copper is 0.386J/g°C
Learn more at: brainly.com/question/16787162?referrer=searchResults
