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NeTakaya
2 years ago
5

Which of the following mixtures is not a colloid? gradpo!nt

Chemistry
1 answer:
Effectus [21]2 years ago
6 0

Milk

Explanation:

because milk is very thick youknow here I go

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The answer is B, sodium is an element.
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If mixture didn't exist how would life be different​<br><br>PLEASEEE QUICKKKK
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boring

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¿Cómo se escribe la fórmula molecular (orden de los iones)?
cluponka [151]

Answer:

A la izquierda el catión y a la derecha el anión.

Explanation:

¡Hola!

En este caso, y basado en las normas IUPAC para la escritura de las fórmulas moleculares, es necesario primero escribir el catión a la izquerda, seguido del anión a la derecha, tal y como se muestra en los siguientes ejemplos, recordando que el catión es el ion cargado positivamente y el anión, negativamente:

K^+Cl^-\\\\Ag_2^+(SO_4)^{2-}

Los cuales son cloruro de potasio y sulfato de plata respectivamente. También es necesario tener en cuenta que los metales tienden a ser cationes por su capacidad de perder electrones, mientras que los no metales a ganarlos y por ende resultar como aniones.

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6 0
3 years ago
How many anions are in 0.500 g of MgBr2
Oksana_A [137]

<u>Given:</u>

Mass of MgBr2 = 0.500 g

<u>To determine:</u>

Number of anions in 0.500 g MgBr2

<u>Explanation:</u>

Molar mass of MgBr2 = 24 + 2 (80) = 184 g/mol

Moles of MgBr2 = 0.500 g/184 g.mol-1 = 0.00271 moles

Based on stoichiometry-

1 mole of MgBr2 has 1 mole of Mg2+ cations and 2 moles of Br- anions

Therefore, 0.00271 moles of MgBr2 will have: 2 * 0.00271 = 0.00542 moles of Br-

Now,

1 mole of Br- contains 6.023 * 10²³ anions

0.00542 moles of Br- contain: 0.00542 * 6.023*10²³ = 3.264*10²¹ anions

Ans: There are 3.264*10²¹ anions in 0.5 g of MgBr2


4 0
3 years ago
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