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NeTakaya
2 years ago
5

Which of the following mixtures is not a colloid? gradpo!nt

Chemistry
1 answer:
Effectus [21]2 years ago
6 0

Milk

Explanation:

because milk is very thick youknow here I go

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Fill in the blank for the following statement: ________ is the movement of rocks, sand, or materials from a place?
Verizon [17]

Answer:

Erosion.

Explanation:

It can be as small as a grain of sand or as large as a boulder. Sediment moves from one place to another through the process of erosion. Erosion is the removal and transportation of rock or soil. Erosion can move sediment through water, ice, or wind.

3 0
2 years ago
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True or false solubility tells u how fast a solute will dissolve?
Nina [5.8K]
Solubility <span>is a measurement that describes how much solute dissolves in a given amount of solvent</span>                                    
4 0
3 years ago
Magnesium occurs in seawater to the extent of 1.4 g magnesium per kilogram of seawater. What volume of seawater, in cubic meters
NISA [10]

Answer: 6.3\times 10^7m^3

Explanation:

Required amount of magnesium = 1.00\times 10^5 tons

Given : 1 ton = 2000 lb

1.00\times 10^5 tons=\frac{2000}{1}\times 1.00\times 10^5=2\times 10^8lb

1 lb = 453.592 g

2\times 10^8 lb=\frac{453.592 }{1}\times 2\times 10^8 lb=907.184\times 10^8g

Given : 1.4 g of magnesium is produced by 1000 g of sea water

907.184\times 10^8g of magnesium is produced by =\frac{1000}{1.4}\times 907.184\times 10^8g=6.5\times 10^{13} g of sea water

Density of sea water  = 1.025 g/ml

Volume of sea water =\frac{\text {mass of sea water}}{\text {density of sea water}}=\frac{6.5\times 10^{11}g}{ 1.025g/ml}=6.3\times 10^{13}ml

1 ml = 10^{-6}m^3

6.3\times 10^{13}ml=\frac{10^{-6}}{1}\times 6.3\times 10^{13}=6.3\times 10^7m^3

Volume of seawater, in cubic meters is 6.3\times 10^7

8 0
3 years ago
Consider the following reaction:
Harlamova29_29 [7]

Answer: In 1860s, Norwegian scientists C. M. Guldberg and P. Waage noted a peculiar relationship between the amounts of reactants and products in an equilibrium. Today, we call this observation the law of mass action. It relates the amounts of reactants and products at equilibrium for a chemical reaction. For a general chemical reaction occurring in solution, aA + bB ⇄ cC + dD the equilibrium constant, also known as Keq, is defined by the following expression: Keq = [C]c/[D]d where [A] is the molar concentration of species A at equilibrium, and so forth. The coefficients a, b, c, and d in the chemical equation become exponents in the expression for Keq. The Keq is a characteristic numerical value for a given reaction at a given temperature. That is, each chemical reaction has its own characteristic Keq. The concentration of each reactant and product in a chemical reaction at equilibrium is related; the concentrations cannot be random values, but they depend on each other. The numerator of the expression for Keq has the concentrations of every product (however many products there are), while the denominator of the expression for Keq has the concentrations of every reactant, leading to the common products over reactants definition for the Keq. Let us consider a simple example. Suppose we have this equilibrium: A ⇄ B .There is one reactant, one product, and the coefficients on each are just 1. The Keq expression for this equilibrium is Keq = [B]/[A]. Exponents of 1 on each concentration are understood. Suppose the numerical value of Keq for this chemical reaction is 2.0. If [B] = 4.0 M, then [A] must equal 2.0 M so that the value of the fraction equals 2.0: Keq = [B]/[A] = 4.0/2.0 =2.0 .By convention, the units are understood to be M and are omitted from the Keq expression. Suppose [B] were 6.0 M. For the Keq value to remain constant (it is, after all, called the equilibrium constant), then [A] would have to be 3.0 M at equilibrium: Keq = [B]/[A] = 60/3.0= 2.0 .If [A] were not equal to 3.0 M, the reaction would not be at equilibrium, and a net reaction would occur until that ratio was indeed 2.0. At that point, the reaction is at equilibrium, and any net change would cease. However, that the forward and reverse reactions do not stop because chemical equilibrium is dynamic.

7 0
3 years ago
A lab requires 3.50L of a 2.0M solution of HCl. What volume of a 6.0M solution is needed to make this solution?
Alchen [17]
The answer is 1.167L of 6.0M solution.

4 0
3 years ago
Read 2 more answers
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