Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.
Explanation:
Given: 
= 61 L, 
= 183 K, 
= 0.60 atm
At STP, the value of pressure is 1 atm and temperature is 273.15 K.
Now, formula used to calculate the new volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.
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brainly.com/question/1122074
Answer:
1.728 mol /(L*min)
Explanation:
Hello,
In the attached photo, you'll find the numerical procedure for your question.
- Take into account that the negative sign is eligible for reagents and positive for products.
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Answer:
Explanation:
As
Molar mass of NaCl= 58.44 gm
So we got it that,
58.44 mass of NaCl contain = 6.023*10^23 molecules of Na Cl
x mass will contain = 6.78*10^50
by cross multiplication , we get
x= 58.44*(6.78*10^50)/ 6.023*10^23
x= 65.785 * 10^27 molecules
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1. Ca(HCO3)2
2.Ca(HCOO)2
3. Ca(OH)2
4.NaOH
5.KCI
6.MgSO4
7.PbO
8.HCl
9.HNO3
10.H2SO4
11.NH3
12.(NH4)3PO4
13.NaOH
:)
