Answer - B Atoms in the original substances are arranged in a different way to make new substances
Answer:
isopropyl benzene (cumene)
Explanation:
The reaction of isopropyl chloride and AlCl3 and benzene belongs to the class of organic reactions known as the Friedel Kraft alkylation.
The mechanism of the reaction involves the formation of a tetrahedral complex [AlCl4]^-.
The electrophile now is the isopropyl group which attacks the benzene to yield the product.
The molarity of the solutions are as follows:
- solution B has the highest molarity
- solutions A, D and F have the same molarity
- solutions A and C are mixed together have a lower molarity than B
- solution F and D will have the same molarity
- Volume of water required to be evaporated is 8.3 mL
<h3>What is molarity of a solution?</h3>
The molarity of a solution is the amount in moles of a substance present in a given volume of solution.
From the image of the solution given:
- solution B has the highest molarity
- solutions A, D and F have the same molarity
- when solutions A and C are mixed, the resulting solution have a lower molarity than B
- solution F and D will have the same molarity after 75 mL and 50 mL of water are added to each respectively
- the molarity of B is 12/50 = 4/16.7. Volume of water required to be evaporated = 25 - 16.7 = 8.3 mL
Therefore, the molarity of the solutions depends on the moles of substance present per given volume of solution.
Learn more about molarity at: brainly.com/question/24305514
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Answer:
See explanation
Explanation:
The question is incomplete because the image of the alcohol is missing. However, I will try give you a general picture of the reaction known as hydroboration of alkenes.
This reaction occurs in two steps. In the first step, -BH2 and H add to the same face of the double bond (syn addition).
In the second step, alkaline hydrogen peroxide is added and the alcohol is formed.
Note that the BH2 and H adds to the two atoms of the double bond. The final product of the reaction appears as if water was added to the original alkene following an anti-Markovnikov mechanism.
Steric hindrance is known to play a major role in this reaction as good yield of the anti-Markovnikov like product is obtained with alkenes having one of the carbon atoms of the double bond significantly hindered.
