Given:


To find:
The quadrant of the terminal side of
and find the value of
.
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,


Here cos is positive and sine is negative. So,
must be lies in Quadrant IV.
We know that,



It is only negative because
lies in Quadrant IV. So,

After substituting
, we get





Therefore, the correct option is B.
Answer:
28.25
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given:



12, 13, 15, 15, 16, 19,19,19,20,21,25 what is the median?
Olin [163]
The median is the middle number.
The middle number is 19.
Median = 19.
Hope this helped.
Answer:
In Heather's solution to the problem, she wrote and solved an equation.
Her work is:
Step 1: 1.08(x +9.01 +0.98 +5.01) = 21.87
Solving like terms
1.08(x+15}=21.87
dividing both side by 1.08
we get
x+15=21.87/1.08
x+15=20.25
subtracting both side by 13.9198
x=20.25-15
x=5.25
According to correction
;
<u>Option </u><u>1</u><u>st</u>
<u>yes,it is correct.</u>