3) Answer: 8:9 (Defense:Offense)
16 and 18 need to be simplified. They're both divisible by 2, getting 8:9, and can't be simplified any more or they won't be whole numbers.
4) Answer: 1:3 (Hit:Bat times)
5 and 15 are divisible by 3, making 1 and 3.
5) Answer: 1:65 (Hours:Miles)
3 and 195 is divisible by 3. (195 is divisible by 3 because 1+9+5=15, getting the sum of numbers will get a smaller number, and if that number, 15 in this case, is divisible by 3, then the larger number is divisible by 3. 195/3=65, so 1:65
6) Answer: 1:3 (Potatoes:Servings)
8 and 24 is divisible by 8, getting 1 and 3.
Answer:
Tienes 3 números, "x", "y", "z"
=> El primero es 20 unidades menor que el segundo:
El primero es "x", y el segundo es "y", entonces:
x = y - 20
=> El tercero es igual a la suma de los dos primeros:
El tercero es "z", entonces:
z = x + y
z = (y - 20) + y
z = 2y - 20
=> Entre los tres suman 120
x + y + z = 120
y - 20 + y + 2y - 20 = 120
4y - 40 = 120
4y = 160
y = 40
Si y = 40, entonces:
x = y - 20
x = 20
Además, z = 2y - 20
z= 60
RPTA:
x=20
y=40
z=60
Step-by-step explanation:
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
Answer:
uhmm. lemme remember how to do that
Answer:
1,498,420
Step-by-step explanation:
