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valina [46]
3 years ago
10

If three pears and four oranges cost $4.85 and three pears and ten oranges cost $8.75 what is the cost of a pear and an orange

Mathematics
1 answer:
marishachu [46]3 years ago
4 0

Answer:

1 pear = $0.75; 1 orange = $0.65

Step-by-step explanation:

(1)               3P +  4O = 4.85

(2)              3P + 10O = 8.75                 Eqn (2) - Eqn (1)

3P + 10O – 3P – 4O = 8.75 – 4.85     Combine like terms

                           6O = 3.90                 Divide each side by 6

                             O = $0.65              Substitute into Eqn (1)

           3P + 4×0.65 = 4.85

               3P + 2.60 = 4.85                 Subtract 2.60 from each side

                           3P = 2.25                Divide each side by 3

                            P = $0.75

Oranges cost $0.65 each and pears are $0.75 each

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3 years ago
Which equation has the solution y=2?
antoniya [11.8K]

Answer:

<h2>3y + 2 = 8</h2>

Step-by-step explanation:

solve A

2y - 3 = 19

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solve B

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solve C

4y - 4 = -4

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solve D

5y + 1 = 10

5y = 9

y = 9/5



7 0
3 years ago
HURRY
Alex73 [517]
$3, $1, $5, $2, $3, $9, $1 = $24 - $1 = $23 - $1 = $22.

$22 is the estimation of the bill when all of the amounts are rounded to the nearest dollar. The estimation is greater than the total bill which is 23 cents less than the estimation. The total on the register is reasonable and accurate.
3 0
3 years ago
Simplify the expression.<br><br>(1.08 x 10^-3) x (9.3 x 10^-3) ÷ 0.1
AlekseyPX
<span>1.2555⋅<span>10^<span>−<span>6  
</span></span></span></span>Explanation:

<span><span><span>(1.08⋅<span>20<span>−3</span></span>)</span><span>(9.3⋅<span>10<span>−3</span></span>)</span>=<span>1.08<span><span>(20)</span>3</span></span>⋅<span>9.3<span><span>(10)</span>3</span></span>=<span><span>1.08⋅9.3</span><span>8⋅<span>106</span></span></span>=1.2555</span><span>⋅<span>10<span>−6</span></span></span></span>

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Step-by-step explanation:

3 0
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