Answer:
The correct option is;
Increasing one fifth unit/sec
Step-by-step explanation:
The equation that gives the curve of the particle of the particle is y = 5·x² - 1
The rate of decrease of the y value dy/dt = 2 units per second
We have;
dy/dx = dy/dt × dt/dx
dy/dx = 10·x
dy/dt = 2 units/sec
dt/dx = (dy/dx)/(dy/dt)
dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)
When x = 1
dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec
dx/dt = 1/5 unit/sec
Therefore, x is increasing one fifth unit/sec.
Answer:
Step-by-step explanation:
Given
Required
Find the measure of a
Since there is no diagram to support the question, we'll assume that:
This gives:
Subtract 22 from both sides
I wrote down the answer cuz it’s just easier to read that way:)
Substitute the input (x) numbers for x . Example: y= 5x substitute -3 for X
5 x -3 = -15. So there's your first answer for the first chart.
