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3 years ago

10

. One measure of variability is __________________, which is the mean distance between each data value and the mean of the data

set. *
A.measure of center
B.mean
C.measure of variablity
D.mean absolute deviation (MAD)

1 answer:

IgorLugansk [536]3 years ago

5 0

D. Mean absolute deviation (MAD)

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Find the lateral area of the prism. 27 sq. ft. 36 sq. ft. 54 sq. ft. Find the total area of the prism. T.A.= Find the volume.

Yakvenalex [24]

The volume would be 54 sq. f.

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3 years ago

Read 2 more answers

What is the solution to -x2 + 5x - 10 = 0?

Korolek [52]

Answer:

No solution

Explanation

−x^2+5x−10=0

Step 1: Use quadratic formula with a=-1, b=5, c=-10.

you plug it in as shown below

and simplify

when you simplify

you get

as shown below

This is no solution....

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3 years ago

On the following number line, two rational numbers are graphed.Represent the two numbers as fractions (or mixed numbers) in lowe

nordsb [41]

The first graphed rational number is at the middle of -2 and -1, thus the number represented is $-1 \frac{1}{2}$

The second graphed number is five out of six places from from 0 to 1, thus the number graphed is $0+ \frac{5}{6} = \frac{5}{6}$

The difference between the two numbers can be represented as
$-1 \frac{1}{2} - \frac{5}{6}$
or
$\frac{5}{6} -(-1 \frac{1}{2} )= \frac{5}{6} +1 \frac{1}{2}$

To find the difference,

$-1 \frac{1}{2} - \frac{5}{6} \\ \\ =-1 \frac{3+5}{6} \\ \\ =-1 \frac{8}{6} =-2 \frac{2}{6} \\ \\ =-2 \frac{1}{3}$

Also,

$\frac{5}{6} +1 \frac{1}{2} \\ \\ =1 \frac{5+3}{6} \\ \\ =1 \frac{8}{6} =2 \frac{2}{6} \\ \\ =2 \frac{1}{6}$

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4 years ago

Simplify the expression.<br><br> (−2g5h2)5

vampirchik [111]

I am sure you are trying to type

$( - 2 {g}^{5} {h}^{2} {)}^{5}$
If that is it, then you should recall the law of exponents which says,

$({a}^{m} {)}^{n} = {a}^{mn}$
Let us share the exponent for each of them.

$( - 2 {g}^{5} {h}^{2} {)}^{5} = ( { - 2)}^{5} ( { {g}^{5}) }^{5} ( { {h}^{2}) }^{5}$
We now apply the law,

$( - 2 {g}^{5} {h}^{2} {)}^{5} = ( { - 2)}^{5} ( { {g}^{5 \: \times 5}) }^{} ( { {h}^{2 \times 5}) }^{}$
We now simplify to obtain,

$( - 2 {g}^{5} {h}^{2} {)}^{5} = -32 {g}^{25} {h}^{10}$

If that is not the expression let me know so I will know how to help you

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3 years ago

Given isosceles ABC, median BD to base AC. Prove ADB=CDB. AB=, AD=, BD=, ADB=

lesya692 [45]

Answer:

1. AB=CB def of isosceles triangle

2. AD=CD DEF of median

3. BD=DB reflexive property

4. ADB=CDB SSS

Step-by-step explanation:

ummmm its just the right answer trust

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3 years ago