Find three consecutive intergers such that three times the third is 102 more than the sum of the first and second.
1 answer:
Answer:
A) x + x+1 + x+2
We don't need equation A)
B) 3*(x+2) = (x + X+1) +102
3x + 6 = 2x + 1 + 102
x = 97
Numbers are 97, 98 and 99
Step-by-step explanation:
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