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alexdok [17]
3 years ago
13

Does the table represent a function?

Mathematics
2 answers:
asambeis [7]3 years ago
4 0
Yes, the table represents a function.

None of the independent (x) values are repeated and each one has a corresponding (y) value.

If you had a repeated (x) value in the table, it would not represent a function.
Alinara [238K]3 years ago
4 0

Answer:

The table represents a function

Step-by-step explanation:

a function is a map from non-empty set A to a non-empty set B such that every element of A is mapped to a unique element of B.

As we can see from the table that corresponding to every x, there exist a unique image y

(f(-2)=7

f(-1)=4

f(0)=3

f(1)=4

f(2)=7)

Hence, The table represents a function.

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You have $50 in your savings account and plan to deposit $10 each week. Your friend has $25 in her savings account and plans to
Mariulka [41]

Answer: 50+10x

Answer: 25+10x

Answer: No. 50+10x=25+10x. In simplified form, it is 0 =25 which is undefined (no solution).

7 0
2 years ago
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Someone please help asap!!!!! difference of squares
AnnZ [28]

Answer:

The answer to your question is: the last option

Step-by-step explanation:

                                                      m² - 6m + 6m -36

Simplify like terms                                m² - 36    

Factor (difference of squares)        (m + 6) (m - 6)

4 0
3 years ago
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
Find the indicated limit, if it exists.
kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Limit Property [Addition/Subtraction]:                                                                   \displaystyle \lim_{x \to c} [f(x) \pm g(x)] =  \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}

<u>Step 2: Find Right-Side Limit</u>

  1. Substitute in function [Limit]:                                                                         \displaystyle  \lim_{x \to 5^+} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 5^+} 5 - x = 5 - 5 = 0

<u>Step 3: Find Left-Side Limit</u>

  1. Substitute in function [Limit]:                                                                         \displaystyle  \lim_{x \to 5^-} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

∴ Since  \displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)  , then  \displaystyle \lim_{x \to 5} f(x) = DNE

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Limits

5 0
3 years ago
Find the equation of this line.<br> Acellus
aalyn [17]

Answer:

Step-by-step explanation:

two points on the line are (-3,-2) and (5,4)

slope=(4+2)/(5+3)=6/8=3/4

eq. of line is

y+2=3/4 (x+3)

4y+8=3x+9

4y=3x+1

y=3/4 x+1/4

8 0
2 years ago
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