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3 years ago

Complete : 973 mg = 0.973

1 answer:

8 0

Well, to get from 973 to .973 you would have had to divide by 1000. And since we know that there are 1000mg in one gram we can conclude that 973mg/1000mg = .973 grams

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According to a Gallup survey conducted in July 2011, 20% of Americans favor reducing the U.S. budget deficit by using spending c

Yakvenalex [24]

Answer:

Option C is correct.

The test statistic for this question is -3.13

Step-by-step explanation:

To compute the z-test statistic, the formula is given as

z = (x - μ₀)/σₓ

x = p = sample proportion of the 500 college students sampled, that favor reducing the deficit using only spending cuts with no tax increase = (75/500) = 0.15

μ₀ = p₀ = the proportion to be compared against, that is, the proportion of Americans that favor reducing the U.S. budget deficit by using spending cuts only, with no tax increases = 20% = 0.20

σₓ = standard error of the sample proportion = √[p(1-p)/n]

p = 0.15

n = Sample size = 500

σₓ = √[0.15×0.85/500] = 0.01597

z = (0.15 - 0.20) ÷ 0.01597

z = -3.13

Hope this Helps!!!

8 0

3 years ago

For the questions, imagine a segment in a plane. Use that information to help you answer the questions.

Mars2501 [29]

1 a
2 c
3 a

Hope this help :)

7 0

3 years ago

144 cubic meters in inches.

nevsk [136]

Answer:

I think is 8.787e+6 cubic inches.

8 0

3 years ago

38 degrees 2x degrees +6 degrees

ratelena [41]

STEP
1
:
Pulling out like terms

Pull out like factors :

32 - 2x = -2 • (x - 16)

STEP
2
:

Equations which are never true:

2.1 Solve : -2 = 0

This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:

2.2 Solve : x-16 = 0

Add 16 to both sides of the equation :
x = 16

5 0

3 years ago

Media experts claim that daily print newspapers are declining because of Internet access. Listed below, from left to right and

yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(d) The p value is 1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean, $\bar{x}_{1}$ = 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean, $\bar{x}_{2}}$ = 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

$t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}$

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic $t_{\alpha/2}$ = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

5 0

3 years ago