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rusak2 [61]
3 years ago
13

Find one positive angle whose sine is negative 0.70.

Mathematics
1 answer:
Svetach [21]3 years ago
3 0

Answer:

  • <u><em>Both 2.34 radians and 5.48 radians (approximately) are positive angles whose sine is - 0.70</em></u>

<u><em></em></u>

Explanation:

The <em>sine</em> is the y-coordinate of the point on the unit circle.

The graph shows that, in the first quadrant, the point with y-coordinate = 0.7 has an angle of 0.8 radians (you read it by moving horizontally to the right from the y-axis at the height of 0.70).

Hence, the sine of 0.8 radians is 0.70 (positive).

The sine is negative in the third and fourth quadrants (the y-coordinate is negative below the y-axis).

Then, 0.8 radians is your reference angle.

  • The positive angle in the third quadrant is π radians - reference angle. This is, π radians - 0.8 radians ≈ 3.14 radians - 0.8 radians = 2.34 radians.

  • The positive angle in the fourth quadrant if 2π radians - 0.8 radians ≈ 6.28 radians - 0.8 radians = 5.48 radians.
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Rita makes and sells necklaces. The materials to make each necklace cost $2.75. Last week she made 8 necklaces and wants to make
Tresset [83]

Answer:

The error she made was that she was adding x and 2.75. She should subtract 2.75 from x.

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Step-by-step explanation:

The error she made was that she was adding x and 2.75.

She should write the equation as 8 (x - 2.75) = 78; as she spends $2.75 to make a necklace.

By using the correct equation: 8 (x - 2.75) = 78

=> 8x - 22 = 78

=> 8x = 78 + 22

=> 8x = 100

=> x = 100/8

=> x = 12.5

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Hope this helps you.

3 0
3 years ago
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Answer:

(-3,10) (0,5) (3,0) (6,-5)

Step-by-step explanation:

x intercept = 3

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3 years ago
if the sum of two numbers is four and the sum of their squares minus three times their product is 76, find the numbers
Sauron [17]

Answer:

Numbers =(6,-2 )

Step-by step explanation:

Given

the sum of two numbers is four and the sum of their squares minus three times their product is 76,

Let the first term =X

Second term will be=4-x

So

X^2+(4-x)^2-3x(4-x)=76

x^2+16+x^2-8x-12x+3x^2=76

5x^2-20x+16=76

5x^2-20x-60=0

5(x^2-4x-12)=0

So x^2-4x-12=0

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x^2-6x+2x-12=0

X(x-6)+2(x-6)=0

(X-6)(X+2)=0

X=6,-2

Let X=6 and -2 then numbers will be 6 and (4-6)=-2

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just olya [345]
B. Double 5 plus 1 equals 11 and add 1 to 5 doubled equals 12.
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