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-Dominant- [34]
3 years ago
15

tyrell went to the park to go jogging. the beginning of the running path has an elevation of - 2 feet. the highest elevation on

the jogging path is 14 feet. what is the difference in elevation between the highest point and the beginning of the path?
Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0
I think you have to subtract the numbers like 14-(-2)
=16
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Help me im adding and subtracting integers plssss 40 points!!!!!! for it
Evgen [1.6K]

Answer and Step-by-step explanation:

Simply just adding and subtracting.

8 - 1 - 6 + 5 = 6

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4 0
3 years ago
On a drawing, the scale is 1 centimeter to 30 centimeters. Which of the following is not correct? actual length = 150 cm; drawin
Brrunno [24]

Answer:

drawing length = 7 cm; actual length = 200 cm

Step-by-step explanation:

The ratio is 1 cm in the drawing is 30 cm in actuality.

If the drawing is 5 cm, multiply by 5

5*1 to get the 5 cm drawing and 5*30 to 150 cm in actual length

5cm drawing = 150 cm actual

11cm drawing  multiply by 11

11*1= 11 and 11*30 = 330 cm

11 cm drawing = 330 cm actual

7cm drawing  multiply by 7

7*1= 7 and 7*30 = 210 cm

7 cm drawing = 210 cm actual

8cm drawing  multiply by 8

The one that is not correct: drawing length = 7 cm; actual length = 200 cm

8*1= 8 and 8*30 = 240 cm

8 cm drawing = 240 cm actual

3 0
3 years ago
I need help with this
densk [106]
Add them all up and divide by how many numbers there are in the set
4 0
3 years ago
The number of square feet per house is normally distributed with a population standard deviation of 154 square feet and an unkno
11111nata11111 [884]

Answer: (1500.66,1599.34)

Step-by-step explanation:

Confidence interval for population mean:

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

,where \overline{x} = Sample mean , n= Sample size, z* = critical two tailed z-value , \sigma = population standard deviation.

As per given , we have

n= 16

\sigma = 154 square feet

\overline{x}= 1550 square feet

\alpha= 1-0.80 = 0.20

Critical z-value = z_{\alpha/2}=z_{0.2/2}=z_{0.1}=1.2815

Confidence interval for population mean:

1550\pm (1.2815)\dfrac{154}{\sqrt{16}}\\\\ = 1550\pm (1.2815)\dfrac{154}{4}\\\\= 1550\pm 49.33775\\\\ =(1550-49.33775,\ 1550+49.33775)\\\\\approx (1500.66,\ 1599.34)

Required confidence interval:  (1500.66,1599.34)

6 0
3 years ago
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