All categories

3 years ago

Find the radius of a circle with a circumference of 35 pie yards

Mathematics

1 answer:

natita [175]3 years ago

8 0

Answer:

Using the formula

C=2πr

Solving for r

r=C

2π=35

2·π≈5.57042

Step-by-step explanation:

You might be interested in

What is the length of the side opposite the 60° angle?

Zina [86]

Answer: 90

Step-by-step explanation:

opposite side is 90

4 0

2 years ago

Read 2 more answers

Only do question 17 50 points Topic: Percentage

ZanzabumX [31]

Answer:

see below

Step-by-step explanation:

Cedarville

Year 1

1200 * 8% = 96 people

At the end the population is 1296

Year 2

1296 * 7% =90.72

1296+90.72 =1386.72 people

Pinedale

1200*15%=180

1200+180 = 1380

Cedarville has more people at the end of 2 years by 6.72 people

3 0

3 years ago

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

8 0

3 years ago

Y-x=15 y-x=5 using elimination

Galina-37 [17]

Answer:

No solution

Step-by-step explanation:

To eliminate is to get rid of one of the variables.

You can choose to either add each term in the equations or subtract each term in the equation.

For a variable to be eliminated, there must one pair that have the same constant with it. Each equation already has the same constant with a variable.

Try adding them.

. y - x = 15

+ y - x = 5

2y - 2x = 20 No variables were eliminated.

Try subtracting.

. y - x = 15

- y - x = 5

0y - 0x = 10 All variables were eliminated.

. 0 = 10 This is false.

This system of equations cannot be solved.

Graphically, these two lines would have the same slope and are parallel. The solution to a system is same as the point of intersection. Parallel lines never meet, never intersect, therefore there is no solution.

3 0

3 years ago

Which point is the image of point R(4, -7) first reflected across the x-axis and then across the y-axis?

nasty-shy [4]

Answer:

(-4, 7)

Step-by-step explanation:

It would be the exact opposite of point R because it was rotated about 180 degrees from it's original location

6 0

2 years ago